Answer:
a)3312 x 10⁴ J
b)I = 57.5 A
c)9200 W
Explanation:
Given that
P =4600 W
Time t= 2 h = 2 x 3600 s= 7200 s
We know that
1 W = 1 J/s
a)
Energy stored in the battery = P .t
=4600 x 7200 J
=3312 x 10⁴ J
b)
We know that power P given as
P = V .I
V=Voltage ,I =Current
4600 = 80 x I
I = 57.5 A
c)
The energy supplied = 4600 x 2 = 9200 W
6,000 in scientific notation is 6 x 10^3.
6 x 10^3 = 6,000
Hope this helps ! <3
The answer should be 741 N.
W=m*g
9.5*78 is 741
Answer:
KE = 2.03 J
Explanation:
After impact, the kinetic energy of the bullet+block will convert to potential energy
½mv² = mgh
v = √(2gh) = √(2(9.81)(0.00500) = 0.0981 m/s
conservation of momentum during the collision
0.015u + 2.50(0) = (2.50 + 0.015)(0.0981)
u = 16.4481 m/s
KE = ½mv² = ½(0.015)16.4481² = 2.0290499...
KE = 2.03 J
The absolute uncertainty in the volume of the cube is 0.06 m³.
We need to know about the uncertainty of measurement to solve this problem. The uncertainty of cube volume can be determined by
V = s³
|ΔV| = dV/ds x Δs
where V is volume, s is length, ΔV is uncertainty in the volume and Δs is the uncertainty of length.
From the question above, we know that
s = 1.00 m
Δs = 2% of s = 2/100 x 1 = 0.02 m
By using the uncertainty of volume formula, we get
|ΔV| = dV/ds x Δs
|ΔV| = d(s³)/ds x Δs
|ΔV| = 3s² x Δs
|ΔV| = 3. 1² x 0.02
|ΔV| = 0.06 m³
Hence, the uncertainty in the volume is 0.06 m³.
Find more on uncertainty at: brainly.com/question/1577893
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