Impulse = Force * times and also Impulse = change in momentum.
Given that the mass does not change, change if momentum = mass * (final velocity - initial velocity)
Given that you know mass and initial velocity (which is the velicity before the cart hits the wall) you need the final velocity (which is the velocity after the cart hits the wall).
Answer: the velocity of the cart after it hits the wall.
To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as
, the relation with the final volume as



Initial temperature = 
Let T be the temperature after expanding by the formula of volume expansion
we have,

Where
is the volume coefficient of copper 




Therefore the temperature is 53.06°C
F equals 3N with respect to the circle's center, moving in the same direction as the centripetal acceleration.
<h3>How much centripetal force is there in a centrifuge?</h3>
Centripetal force is the force that pushes an item in the direction of its center of curvature. It is fundamental to how a centrifuge operates.
<h3>On a roller coaster, what is centripetal force?</h3>
An item travelling in a circle is pushed inward toward what is known as the center of rotation, which is essentially what a roller coaster accomplishes when it travels through a loop. The force that maintains an object moving along a curved route is this pull toward the center, or centripetal force.
To know more about centripetal force visit:-
brainly.com/question/11324711
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Good afternoon.
We have:

The function of velocity:

For
t = 5 s: