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erastovalidia [21]
3 years ago
12

A 10.0-mL solution of 0.30 M NH3 is titrated with a 0.100 M HCl solution. Calculate the pH after the following additions of the

HCl solution:
a) 0.00 mL b) 10.0 mL c) 30.0 mL d) 40.0 mL
Chemistry
1 answer:
yulyashka [42]3 years ago
3 0
Iojioujuu0u909uoiohuy
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Give the values of n, l and ml for: (a) each orbital in the 2p subshell, (b) each orbital in the 5d subshell.?
SCORPION-xisa [38]

Hey there!:

* For 2p subshell :

n = 2, l =1, ml = -1, 0, +1

* for 5d subshell,

n = 5, l = 2, ml = -2, -1, 0, +1, +2


Hope that helps!

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What is the energy produced through cellular respiration called?
tresset_1 [31]

Answer:

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4 0
3 years ago
A sodium ion, Na+, with a charge of 1.6×10−19C and a chloride ion, Cl− , with charge of −1.6×10−19C, are separated by a distance
sasho [114]

Answer:

W\geq 2.1x10^{-19}J

Explanation:

Due to Coulomb´s law electric force can be described by the formula F=K\frac{q_{1}.q_{2}}{r^{2}}, where K is the Coulomb´s constant (9x10^{9} N\frac{m^{2} }{C^{2} }), q_{1}= Charge 1 (Na+ in this case), q_{2} is the charge 2 (Cl-) and r is the distance between both charges.

Work made by a force is W=F.d and total work produced is the change in energy between final and initial state. this is W=W_{f} -W_{i}.

so we have W=W_{f} -W_{i} =(K\frac{q_{(Na+)}q_{(Cl-)}rf}{r_{f} ^{2}})-(K\frac{q_{(Na+)}q_{(Cl-)}ri}{r_{i} ^{2}})=Kq_{(Na+)}q_{(Cl-)[\frac{1}{{r_{f}}} -\frac{1}{{r_{i}}}]

Given that ri= 1.1nm= 1.1x10^{-9}m and rf= infinite distance

W=(9x10^{9})(1.6x10^{-19})(-1.6x10^{-19})[\frac{1}{\alpha }-\frac{1}{(1.1x10^{-9})}]=2.1x10^{-19}J

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4 years ago
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fredd [130]

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Tamoxifen is an irreversible, competitive inhibitor.

Explanation:

In order to binds to the active site of the estrogen receptor protein, tamoxifen have to compete with the other chemical compound, and inhibits the estrogen release, so it is a competitive inhibitor. Then, you said that when tamoxifen binds to the receptor,  the protein is permanently deactivated, so it is also irreversible.

8 0
3 years ago
What are the two properties of Graphite that are different from the properties of Diamond?
Rus_ich [418]

Answer:

Graphite is insoluble in water and organic solvents - for the same reason that diamond is insoluble. Attractions between solvent molecules and carbon atoms will never be strong enough to overcome the strong covalent bonds in graphite. conducts electricity.

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