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3 years ago

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Draw the products formed when benzoic acid (C6H5CO2H) is treated with CH3OH having its O atom labeled with 18O (CH318OH). Indica

te where the labeled oxygen atom resides in the products.

1 answer:

GREYUIT [131]3 years ago

6 0

Complete Question

Answer:

The product formed is shown on the first uploaded image

The labeled oxygen resides in the ester functional group $OCH_3$

Explanation:

The mechanism of this reaction is shown on the second uploaded image

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Answer : The molecular formula of benzoyl peroxide is $C_{14}H_{10}O_4$

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Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

As we are given that the molar mass of compound is, 0.242 kg/mol.

Molecular mass = 0.242 kg/mol = 242 g/mol (1 kg = 1000 g)

The empirical mass of $C_7H_5O_2$ = 7(12) + 5(1) + 2(16) = 121 g/eq

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

$n=\frac{242}{121}$

$n=2$

Molecular formula = $(C_7H_5O_2)_n$ = $(C_7H_5O_2)_2$ = $C_{14}H_{10}O_4$

Thus, the molecular formula of benzoyl peroxide is $C_{14}H_{10}O_4$

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<span>We have the following statement data:
</span>
Data:
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</span>
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<span>To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:
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