Ask question

Ask question

All categories

gizmo_the_mogwai [7]

3 years ago

12

PLZ HURRY I NEED THIS ANSWER LIKE... NOW

1 answer:

tresset_1 [31]3 years ago

6 0

Answer:

Check for a change in total mass during the reaction. During the change to a chemical reaction, the mass of the products remain equal, which results in no change of the mass. The mass will change during nuclear reactions because of the large release of energy; that results in the difference of the accumulation. ^_^

You might be interested in

Calculate either [ H 3 O + ] or [ OH − ] for each of the solutions.

STALIN [3.7K]

Answer: Solution A : $[H_3O^+]=0.300\times 10^{-7}M$

Solution B : $[OH^-]=0.107\times 10^{-5}M$

Solution C : $[OH^-]=0.177\times 10^{-10}M$

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

$pH=-\log[H_3O^+]$

$pOH=-log[OH^-}$

$pH+pOH=14$

$[H_3O^+][OH^-]=10^{-14}$

a. Solution A: $[OH^-]=3.33\times 10^{-7}M$

$[H_3O^+]=\frac{10^{-14}}{3.33\times 10^{-7}}=0.300\times 10^{-7}M$

b. Solution B : $[H_3O^+]=9.33\times 10^{-9}M$

$[OH^-]=\frac{10^{-14}}{9.33\times 10^{-9}}=0.107\times 10^{-5}M$

c. Solution C : $[H_3O^+]=5.65\times 10^{-4}M$

$[OH^-]=\frac{10^{-14}}{5.65\times 10^{-4}}=0.177\times 10^{-10}M$

7 0

2 years ago

Horizontal<br> rows are called

klio [65]

In math it’s just horizontal in science it’s periods

5 0

3 years ago

Read 2 more answers

What answer giving brainliest tysm

monitta

Answer:

a

Explanation:

it is repeating

3 0

3 years ago

The half-life of 131I is 80 days. How much of a 500.0 mg sample remains after 3 half lives?

I am Lyosha [343]

Answer:

62.5 mg

Explanation:

Just multiply the original amount by 1/2 three times:

500 mg x 1/2 x 1/2 x 1/2 = 62.5 mg

6 0

1 year ago

What is the name of the molecule below

il63 [147K]

Answer:

2-octene

Explanation:

the 8-carbon chain (oct); has a double bond (ene) is on the 2nd carbon (2-)

4 0

2 years ago