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3 years ago

PLZ HURRY I NEED THIS ANSWER LIKE... NOW

Chemistry

1 answer:

tresset_1 [31]3 years ago

6 0

Answer:

Check for a change in total mass during the reaction. During the change to a chemical reaction, the mass of the products remain equal, which results in no change of the mass. The mass will change during nuclear reactions because of the large release of energy; that results in the difference of the accumulation. ^_^

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Hazardous materials are grouped into classes identifying their.

saveliy_v [14]

Hazardous materials are grouped into classes identifying their similarities in composition and structure.

<h3>Why hazardous materials are grouped into classes?</h3>

The hazardous materials are grouped into classes in order to tell us about the severity of hazard and it is done on the basis of similarity in composition.

So we can conclude that hazardous materials are grouped into classes identifying their similarities in composition and structure.

Learn more about hazardous here: brainly.com/question/7310653

8 0

2 years ago

PLEASE HELP !!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Galina-37 [17]

Answer:

Explanation:

Potential energy

6 0

3 years ago

In the laboratory you dilute 2.49 ml of a concentrated 6.00 m hydrochloric acid solution to a total volume of 50.0 ml. what is t

Marizza181 [45]

Equation: M1V1 = M2V2

Where M = concentration & V = volume

Step 1: Write down what is given and what you are trying to find

Given: M1 = 6.00M, V1 = 2.49mL, and V2 = 50.0mL
Find: M2

Step 2: Plug in the values into the equation

M1V1 = M2V2
(6.00M)(2.49mL) = (M2)(50.0mL)

Step 3: Isolate the variable (Divide both sides by 50.0mL so M2 is by itself)

(6.00M)(2.49mL) / (50.0mL) = M2

Answer: M2 = 0.30M
*Don't forget sig figs & units!

4 0

3 years ago

A gas cylinder under constant pressure, such as one with a moveable piston, initially contains 0.25 moles of neon in 5.0 L. If 0

Mandarinka [93]

Answer:

15L will be the final volume

STEPS:

.50 + .25 = .75

.25/5 ÷ .75/x

(.75*5=3.25)

.25x = 3.25

x=15

quizlet

4 0

3 years ago

Identify the type of interactions involved in each of the following processes taking place during the dissolution of sodium chlo

icang [17]

Answer:

A. Interactions between the ions of sodium chloride (solute-solute interactions).

B. Interactions involving dipole-dipole attractions (solvent-solvent interactions).

C. Interactions formed during hydration (solute-solvent interactions).

D. Interactions involving ion-ion attractions (solute-solute interactions).

E. Interactions associated with an exothermic process during the dissolution of sodium chloride (solute-solvent interactions).

F. Interactions between the water molecules (solvent-solvent interactions).

G. Interactions formed between the sodium ions and the oxygen atoms of water molecules (solute-solvent interactions).

Explanation:

The solution process takes place in three distinct steps:

Step 1 is the separation of solvent molecules.

Step 2 entails the separation of solute molecules.

These steps require energy input to break attractive intermolecular forces; therefore, they are endothermic.

Step 3 refers to the mixing of solvent and solute molecules. This process can be exothermic or endothermic.

If the solute-solvent attraction is stronger than the solvent-solvent attraction and solute-solute attraction, the solution process is favorable, or exothermic (ΔHsoln < 0). If the solute-solvent interaction is weaker than the solvent-solvent and solute-solute interactions, then the solution process is endothermic (ΔHsoln > 0).

In the dissolution of sodium chloride, this process is exothermic.

3 0

3 years ago