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3 years ago

PLZ HURRY I NEED THIS ANSWER LIKE... NOW

Chemistry

1 answer:

tresset_1 [31]3 years ago

6 0

Answer:

Check for a change in total mass during the reaction. During the change to a chemical reaction, the mass of the products remain equal, which results in no change of the mass. The mass will change during nuclear reactions because of the large release of energy; that results in the difference of the accumulation. ^_^

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The following reaction does not proceed to a product: H2O + Cu --> no reaction. Why is that?

Anettt [7]

I think the correct answer would be because copper has a lower activity than hydrogen and cannot replace the bonds in it. Substances that are not oxidizing do not react with copper since the redox potentials are very low. Hope this answers the question.

5 0

3 years ago

Read 2 more answers

A 1.28-kg sample of water at 10.0 °C is in a calorimeter. You drop a piece of steel with a mass of 0.385 kg at 215 °C into it. A

Kryger [21]

Answer:

$T_{2}=16,97^{\circ}C$

Explanation:

The specific heats of water and steel are

$Cp_{w}=4.186 \frac{KJ}{Kg^{\circ}C}$

$Cp_{s}=0.49 \frac{KJ}{Kg^{\circ}C}$

Assuming that the water and steel are into an <em>adiabatic calorimeter</em> (there's no heat transferred to the enviroment), the temperature of both is identical when the system gets to the equilibrium $T_{2}_{w}= T_{2}_{s}$

An energy balance can be written as

$m_{w}\times Cp_{w}\times (T_{2}- T_{1})_{w}= -m_{s}\times Cp_{s}\times (T_{2}- T_{1})_{s}$

Replacing

$1.28Kg\times 4.186\frac{KJ}{Kg^{\circ}C}\times (T_{2}-10^{\circ}C)= -0.385Kg\times 0.49 \frac{KJ}{Kg^{\circ}C} \times (T_{2}-215^{\circ}C)$

Then, the temperature $T_{2}=16,97^{\circ}C$

8 0

3 years ago

To investigate the reactivity of metals a student uses four metals. Each time they added 1 g of the metal to 25 cm³ of sulfuric

Mazyrski [523]

Answer:

Volume of the sulfuric acid (25cm³), same mass of each metal (1g)

Explanation:

In an experiment, the CONTROL VARIABLE also known as constant is the variable that is kept unchanged for all groups in an experiment. This is done in order not to influence the outcome of the experiment.

In this case, students are trying to investigate the reactivity of four different metals. They added 1 g of each metal to 25cm³ of sulfuric acid and recorded the temperature change. Based on the explanation of control variable above, the VOLUME OF SULFURIC ACID (25cm³) and the MASS OF EACH METAL (1g) are the CONTROL VARIABLES because they are the same or unchanged in this experiment.

5 0

2 years ago

David found that water can be created in a lab by burning hydrogen gas in air. He concluded that water is not a compound because

Virty [35]

Hi~~

H2O, commonly known as water, is definitely a compound.

David's conclusion is wrong because the hydrogen gas combined with oxygen from the air to form dihydrogen monoxide, also known as water.

7 0

3 years ago

Using the Br?nsted-Lowry concept of acids and bases, identify the Br?nsted-Lowry acid and base in each of the following reaction

antiseptic1488 [7]

Answer:

$H_2PO_3^-$ is Bronsted Lowry base.

$H_2O$ is Bronsted Lowry acid.

Explanation:

According to the Bronsted Lowry conjugate acid-base theory:

An acid is defined as a substance which donates protons and form conjugate base
A base is defined as a substance which accepts protons and forms conjugate acid.

$H_2PO_3^-(aq)+H2O(l)\rightarrow H_3PO_3(aq)+OH^-(aq)$

$H_2PO_3^-$ is Bronsted Lowry base.It accepts protons and forms conjugate acid $H_3PO_3$

$H_2O$ is Bronsted Lowry acid.It donates protons and forms conjugate base $OH^-$

$(CH_3)_2NH(g)+BF_3(g)\rightarrow (CH_3)_2NHBF_3(s)$

There in no exchange of proton in an above reaction.Neither of the reactants and products are Bronsted Lowry acid or Bronsted Lowry base

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3 years ago