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son4ous [18]
3 years ago
12

If you pitch a baseball with twice the kinetic energy you gave it in the

Physics
1 answer:
Kaylis [27]3 years ago
7 0

Answer:

the magnitude of momentum is √2≈ b

Explanation:

hope that helped

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Answer:

an antibiotic

Explanation:

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An object is 25.0 cm from the mirror, its height is 5.0 cm, and focal length is 8.0 cm. What is the distance from the image to t
Oksana_A [137]
1.) Use the formula to solve - 
             1/f = 1/do + 1/di; Where f = focal length; 1/do + 1/di
             1/f = 1/do + di
            1/8 = 1/25 + 1/?
          .125 = .04 + 1/di
   .125 -.04 = 1/di (transferred .04 to the left side of the equation)
       .085/1 = 1/di
.085di/.085 = 1/.085 (multiplied both sides by di and divided both sides by .085)
               di = 11.76 or 12
2.) Therefore, 12 cm is the distance from the image to the mirror
3 0
3 years ago
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Using numbers to describe kinematic quantities is called what description?
MissTica
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Hi my name is Lexi I'm looking for some friends on here! I I go to Baldwin arts and academics. so can you PLZ be my friend on he
katrin [286]

Answer:

You should use this for work related questions :/

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3 years ago
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A laser emits two wavelengths (λ1 = 420 nm; λ2 = 630 nm). When these two wavelengths strike a grating with 450 lines/mm, they pr
Westkost [7]

A) Order of the first laser: 3, order of the second laser: 2

B) The overlap occurs at an angle of 34.9^{\circ}

Explanation:

A)

The formula that gives the position of the maxima (bright fringes) for a diffraction grating is

d sin \theta = m \lambda

where

d is spacing between the lines in the grating

\theta is the angle of the maximum

m is the order of diffraction

\lambda is the wavelength of the light

For laser 1,

d sin \theta = m_1 \lambda_1

For laser 2,

d sin \theta = m_2 \lambda_2

where

\lambda_1 = 420 nm\\\lambda_2 = 630 nm

Since the position of the maxima in the two cases overlaps, then the term d sin \theta on the left is the same for the two cases, therefore we can write:

m_1 \lambda_1 = m_2 \lambda_2\\\frac{m_1}{m_2}=\frac{\lambda_2}{\lambda_1}=\frac{630}{420}=\frac{3}{2}

Therefore:

m_1 = 3

m_2 = 2

B)

In order to find the angle at which the overlap occurs, we use the 1st laser situation:

d sin \theta = m_1 \lambda_1

where:

N = 450 lines/mm = 450,000 lines/m is the number of lines per unit length, so the spacing between the lines is

d=\frac{1}{N}=\frac{1}{450,000}=2.2\cdot 10^{-6} m

m_1 = 3 is the order of the maximum

\lambda_1 = 420 nm = 420\cdot 10^{-9} m is the wavelength of the laser light

Solving for \theta, we find the angle of the maximum:

sin \theta = \frac{m_1 \lambda_1}{d}=\frac{(3)(420\cdot 10^{-9})}{2.2\cdot 10^{-6}}=0.572

So the angle is

\theta=sin^{-1}(0.572)=34.9^{\circ}

Learn more about diffraction:

brainly.com/question/3183125

#LearnwithBrainly

5 0
3 years ago
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