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2 years ago

6

What is the cause of the beats

1 answer:

mestny [16]2 years ago

3 0

When two sound waves of different frequencies approach the ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - producing beats

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A helium–neon laser emits a beam of circular cross section with a radius r and a power P.?. (a) Find the maximum electric field

olchik [2.2K]

there is a relation between intensity of light beam and the magnitude of electric field.<span>I=(1/2)c<span>ϵo</span>n<span>E2</span>=P/π<span>r2</span></span> <span><span>E2</span>=2P/c<span>ϵo</span>nπ<span>r2</span></span> E= magnitude of electric field n= refractive index of medium <span><span>μo</span><span>ϵ0</span>=1/<span>c2
</span></span>energy= power*time = P*(1m/speed of light)<span><span>energy=(P∗1m)/c</span></span>

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3 years ago

Which square (A, B, C, or D) represents the repeating subunit of the polymer shown?

Yuri [45]

It would be C my dude.

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2 years ago

Read 2 more answers

What is the gravitational field value (g) on planet Saturn with a mass of 5.69 X 1026

Zinaida [17]

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2 years ago

A variable-length air column is placed just below a vibrating wire that is fixed at both ends. The length of the air column, ope

pogonyaev

Answer:

The speed of transverse waves in the wire is 234.26 m/s.

Explanation:

Given that,

Length of wire = 129 cm

Speed of sound in air = 340 m/s

First position of resonance = 31.2 cm

We need to calculate the wavelength

For pipe open at one end and closed at other, there is node at closed end and an anti node at open end for 1st resonance.

At 1st resonance,

$L=\dfrac{\lambda}{4}$

$\lambda=4\times L$

Put the value into the formula

$\lambda=4\times31.2\times10^{-2}$

$\lambda=1.248\ m$

We need to calculate the frequency of sound in pipe

Using formula of frequency

$f=\dfrac{v}{\lambda}$

Put the value into the formula

$f=\dfrac{340}{1.248}$

$f=272.4\ Hz$

We need to calculate the node distance

For the wire, there are 3 segments, so 4 nodes

Node-node distance ,

$L=\dfrac{l}{3}$

$L = \dfrac{129}{3}$

$L=43\ cm$

We need to calculate the wavelength of the wire

Using formula of length

$L=\dfrac{\lambda}{2}$

$\lambda=L\times 2$

Put the value into the formula

$\lambda=43\times2$

$\lambda=86\ cm$

We need to calculate the speed of the wave

Using formula of frequency

$f=\dfrac{v}{\lambda}$

$v=f\times\lambda$

Put the value into the formula

$v=272.4\times86\times10^{-2}$

$v=234.26\ m/s$

Hence, The speed of transverse waves in the wire is 234.26 m/s.

4 0

3 years ago

A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling north at 20.0 m/s. The cars stick together. Assume

ahrayia [7]

Answer:

<em>12.23m/s</em>

Explanation:

<em>Let's recall that</em>

<em />

<em>The Initial momentum in (East)axis = 900 x 15 which is = 13500 N-s </em>

<em> </em>

<em>Initial momentum in (North) axis = 750 x 20 which is = 15000 N-s </em>

<em />

<em>Total initial momentum becomes = √[(13500)^2 + (15000)^2] = 20180.44 N-s </em>

<em> The initial momentum direction is at θ* East of North </em>

<em />

<em> Therefore, tanθ = 13500/15000 = 0.9 = tan42* </em>

<em> tanθ=42</em>

<em> </em>

<em>The speed of the wreckage after collection is,</em>

<em />

<em>Recall that The law of momentum conservation states that </em>

<em>Momentum initial = Momentum final </em>

<em> </em>

<em>20180.44 = (900+750) x v </em>

<em> </em>

<em>v = 12.23 m/s</em>

8 0

3 years ago