If the sugar makes up 25% of the solution, that means the water makes up 75%, or 3/4, of the solution.
Set up a proportion to solve:

Cross multiply:


Therefore, there are 354 grams of water in the solution.
Answer:
The Coriolis effect is an apparent deflection in the paths of moving objects caused by Earth's faster speed near the equator than near the poles. In the solar system, the greatest expression of this effect occurs in planetary atmospheres. On Earth, for example, the air around us moves freely above the ground.
Explanation:
His group's cube was made of <span>D) zinc. Looking up the density values of each of the choices, it can be seen that zinc has the closest density out of all of them. It's actual density has a value of 7.14 g/cm3. The others have density values that are way too far from the average density of 7.4 g/cm3.</span>
Answer:
The frozen balloon shrank because the average kinetic energy of the gas molecules in a balloon decreases when the temperature decreases. This makes the molecules move more slowly and have less frequent and weaker collisions with the inside wall of the balloon, which causes the balloon to shrink a little.
Explanation:{ BOOM}***
Answer:
396 g OF CO2 WILL BE PRODUCED BY 270 g OF GLUCOSE IN A RESPIRATION PROCESS.
Explanation:
To calculate the gram of CO2 produced by burning 270 g of gucose, we first write out the equation for the reaction and equate the two variables involved in the question;
C6H12O6 + 6O2 -------> 6CO2 + 6H2O
1 mole of C6H12O6 reacts to form 6 moles of CO2
Then, calculate the molar mass of the two variables;
Molar mass of glucose = ( 12 *6 + 1* 12 + 16* 6) g/mol = 180 g/mol
Molar mass of CO2 = (12 + 16 *2) g/mol = 44 g/mol
Next is to calculate the mass of glucose and CO2 involved in the reaction by multiplying the molar mass by the number of moles
1* 180 g of glucose yields 6 * 44 g of CO2
180 g of glucose = 264 g of CO2
If 270 g of glucose were to be used, how many grams of CO2 will be produced;
so therefore,
180 g of glucose = 264 g of CO2
270 g of glucose = x grams of CO2
x = 264 * 270 / 180
x = 71 280 / 180
x = 396 g of CO2.
In other words, 396 g of CO2 will be produced by respiration from 270 g of glucose.