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Darina [25.2K]
3 years ago
5

I need help! FAST!!!​

Chemistry
1 answer:
aliina [53]3 years ago
5 0

Answer:

The second answer choice

Explanation:

X seems to list attributes for opaque objects, and y lists attributes of Transparent objects.

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Identify the balanced single displacement reaction.
tekilochka [14]
CuCl2<span> + Fe ⟶ Cu + FeCI</span><span>2</span>
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3 years ago
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Which half-reaction can occur at the anode in a
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The answer is (3). The reaction that can occur at the anode is oxidation reaction which will lose electrons. So (1) and (2) are not correct. For (4) Fe3+ can not lose electrons again.
4 0
3 years ago
Benzene is a minor component of gasoline. The standard molar enthalpy of formation of benzene C7H16(l) is 48.95 kJ/mol. For the
Radda [10]

Answer:

-3135.47 kJ/mol

Explanation:

Step 1: Write the balanced equation

C₆H₆(l) + 7.5 O₂(g) ⇒ 6 CO₂(g) + 3 H₂O(g)

Step 2: Calculate the standard enthalpy change of the reaction (ΔH°r)

We will use the following expression.

ΔH°r = ∑np × ΔH°f(p) - ∑nr × ΔH°f(r)

where,

n: moles

ΔH°f: standard enthalpies of formation

p: products

r: reactants

ΔH°r = 6 mol × ΔH°f(CO₂(g)) + 3 mol × ΔH°f(H₂O(g)) - 1 mol × ΔH°f(C₆H₆(l)) - 7.5 mol × ΔH°f(O₂(g))

ΔH°r = 6 mol × (-393.51 kJ/mol) + 3 mol × (-241.82 kJ/mol) - 1 mol × (48.95 kJ/mol) - 7.5 mol × 0 kJ/mol

ΔH°r = -3135.47 kJ

Since this enthalpy change is for 1 mole of C₆H₆(l), we can express it as -3135.47 kJ/mol.

7 0
2 years ago
Which of the following compounds will experience hydrogen bonding?
lora16 [44]
I believe the answer is the first one <span>NaH</span>
7 0
3 years ago
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In aerobic cellular respiration, if four molecules of pyruvic acid enter steps two, the formation of acetyl CoA and three, the K
BabaBlast [244]

Answer:

The aerobic cellular respiration of the glucose where glucose is converted to energy via four steps as follows

1. Glycolysis (glucose break down to pyruvic acid)

2. Link reaction

3. Krebs cycle

4. Electron transport chain, or ETC

The four pyruvic acid produces Four ATP, twenty NADH, and four FADH_{2} molecules

Explanation:

When four pyruvic acid enters step two of the aerobic cellular respiration, they are converted by Oxidative decarboxylation into acetyl-CoA, four molecules of NADH and four molecule of CO2 are formed. This process is otherwise called the link reaction or transition  step, because it connects or links the Krebs cycle and glycolysis.

From the chemical reactions involved in cellular respiration of one glucose molecule, from two pyruvic acid molecules we have 2 ATP molecules, 10 NADH molecules, and 2 FADH2 molecules

Hence from four pyruvic acid molecules we have that the acetyl-CoA produced from the four pyruvic acid enters the the Krebs cycle and forms four ATP molecules, twenty NADH molecules, and four FADH_{2} molecules.

5 0
3 years ago
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