Answer: The constraints could be lack of materials, funds, or time. Another constraint could be size or shape.
Explanation:
E :)
Protons(+), Neturons (-,+), and Electrons (-)
Answer: The chemical equations are given below.
Explanation:
A balanced chemical reaction follows law of conservation of mass.
This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.
Single displacement reaction is defined as the reaction in which more reactive metal displaces a less reactive metal from its chemical reaction.
General equation representing single displacement reaction follows:
C is more reactive element than element A.
The reactivity of metals is judged by the series known as reactivity series. Elements lying above in the series are more reactive than the elements lying below in the series.
- 1. When solid lead metal is put in the beaker of 0.043 M solution.
Lead lies below in the reactivity series than iron. Thus, it will not replace iron from its chemical reaction.
- 2. When solid iron metal is put in the beaker of 0.044 M solution.
Iron lies above in the reactivity series than lead. Thus, it will easily replace lead from its chemical reaction.
Hence, the chemical equations are given above.
Answer:
The answer to the question is
50 % of the original amount of potassium 40 will be left after one half life or 1.25 billion years
Explanation:
To solve the question we note that the half life is the time for half of the quantity of substance that undergoes radioactive decay to disintegrate, thus
we have
half life of potassium 40 K₄₀ = 1.25 billion years
To support the believe tht the rock was formed 1.25 billion years ago we have
After 1.25 billion years we have
= =0.5 of will be left or 50 % of the original amount of potassium 40 will be left
Answer:
2) 25.0mL aliquots of the solution in problem 1 are titrated with EDTA to the calmagite end point. A blank containing a small measured amount of Mg2+ requires 2.12mL of the EDTA to reach the end point. An aliquot to which the same amount of Mg2+ is added requires 25.88mL of the EDTA to reach the end point.
a. How many mL of EDTA are needed to titrate the Ca2+ ion in the aliquot?
b. How many moles of EDTA are there in the volume obtained in a.?
c. What is the molarity of the EDTA solution?
Explanation:
Given that;
Volume of aliquot = 25mL
Blank reading = 2.12mL
2a)
Volume of EDTA used for Ca²⁺ ion
25.88mL - 2.12mL = 23.76mL
Therefore mL of EDTA needed to titrate the Ca²⁺ ion in the aliquot is 23.76mL
2b)
Molarity of Ca²⁺ ion is 0.0172M
Mole of EDTA =
2c)
Molarity of EDTA = mole of EDTA / Vol. of EDTA