Answer:
2,375 cans
Explanation:
The strategy here is to use the information given to calculate the lethal dosage contained in the number of cans we will compute.
We know the lethal dosage is
Ld = 10.0 g caffeine
and we also know that the oncentration of caffeine is:
2.85 mg/ oz
So our problem simplifies to calculate how many oz will contain the lethal dose, and then given the ounces per can determine how many cans are required.
First convert the lethal dose in grams to mg:
Ld =( 10 g x 1000 mg ) = 10,000 mg caffeine
10,000 mg x ( 1 Oz / 2.85 mg ) = 28,500 oz
28500 oz x ( 1 can/12 oz ) = 2,375 cans
We could also have calculated it in one step using conversion factors:
Number of cans = 10000 mg x 1 oz/ 2.85 mg x 1 can / oz = 2,375 cans
The freezing point depression is a colligative property, which means that it depends on the number of particles of solute disolved in the solution.
When you have solutes that are ionic compounds they dissociate in water into ions, then the compound that dissociates more ions will produce more particles and will decrease the freezing point the most.
Given theses aqueous solutions Na2 CO3, Co Cl3, and Li NO3 you can predict the order of the freezing points.
First, write the dissociation equations>
Na2CO3 -> 2Na(+) + CO3 (2-) These are 3 ions: two of Na(+) and one of CO3(2-)
The number inside parenthesis are number of charge not number of molecules.
Co Cl3 -> Co(3+) + 3 Cl (1-) Those are 4 ions: one of Co (+) and three of Cl (-)
Li NO3 -> Li (+) + NO3 (-) those are two ions: one of Li (+) and one of NO3(-)
Then the ionic compound that dissociates into more ions give the solution with lower freezing point, and these is the rank from higher to lower freezing point:
Li NO3 > Na2 CO3 > Co Cl3.
Answer: physical
Explanation: freezing and melting are physical changes.
Answer: Option C. p-dichlorobenzene and 1,4-dichlorobenzene.
Explanation:
A line-angle formula with six vertices and a circle inscribed corresponds to the compound known as benzene.
Further, according to the IUPAC standards for naming benzene derivatives, you must first number the position of the substituent. In this case, the substituents (chloros) are located at the positions 1 and 4; also, for the benzene derivatives when they have 2 substituents and the positions are 1 and 4, this configuration is known as <em>para </em>or <em>p </em>configuration.
Additionally, this compound has 2 substituents (chloros) so you have to indicate this number (di).
Therefore, the correct answer is C. p-dichlorobenzene and 1,4-dichlorobenzene.
B) It will accelerate to the right because 500 N> 300 N
