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dimaraw [331]
3 years ago
9

Use the APWA 5600 methodology to compute the 1/25 design discharge for the following catchment. The catchment area consists of 1

0 acres of impervious area, 30 acres of apartments and 35 acres of single family housing. The maximum flow path to the outlet is 1000 feet long with the upper catchment slope having an average slope of 1.5% for approximately 150 feet and the remaining slope of the flow path averaging 1.8%.
Engineering
1 answer:
sweet [91]3 years ago
5 0

Explanation:

For a given flow rate, open channel flow based design requires larger conduit sizes than those dimensioned  based on pressure flow. While it may be more expensive to build designed storm drainage systems

Based on open channel flow, this design procedure provides a margin of safety by providing  headroom in the duct to accommodate an increase in flow above the design discharge. Beneath the majority

Under normal conditions, it is recommended that the size of storm drains be based on a gravity flow to full flow criteria  or almost full. The design of the pressure flow may be justified in certain cases. As the hydraulic calculations are  performed, frequent verification of the existence of the desired flow condition should be performed.

Storm drainage systems can often alternate between pressure and open channel flow conditions from one  section to another (Federal Highway Administration, US Department of Transportation, 1996).

For gravity flow conditions, the Manning formula must be edited as described below.

ܳ ൌ

1,486

݊

ܣܴ ଶ / ଷ ܵ ଵ / ଶ

Where:

Q = Discharge, cubic feet per second

A = flow cross-sectional area, square feet

n = Manning roughness coefficient (see Table 5603-1)

ܴ ൌ

ܣ

ܲ

R = hydraulic radius, feet

S = slope in feet per foot

P = wet perimeter in feet

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Pls help me answer my module
Otrada [13]

Answer:

Hand tools based on job requirement and its importance and the classification of hand tools according to its function and its importance are discussed below in details.

Explanation:

Hand tools based on work requirement is essential because Every tool is specifically invented for a particular purpose, so picking the accurate tool will also reduce the amount of energy needed to get work done right without causing injury or harm to either the tools or the exterior being worked on.

classifying of hand tools: wrenches, screwdrivers, cutters, striking tools, hammer tool or struck, pliers, vise, clamps, snips, saws, drills, and knives.

4 0
3 years ago
A 200 W vacuum cleaner is powered by an electric motor whose efficiency is 70%. (Note that the electric motor delivers 200 W of
Goshia [24]

Answer:

The rate at which this vacuum cleaner supply energy to the room when running is 285.71 Watts.

Explanation:

power efficiency of electric motor = 70% = 0.70

The power output of the vacuum cleaner =P_o= 200 W

The power output of the vacuum cleaner = P_i

Efficiency=\frac{P_o}{P_i}

0.70=\frac{200 W}{P_i}

P_i=\frac{200 W}{0.70}=285.71 W

The rate at which this vacuum cleaner supply energy to the room when running is 285.71 Watts.

5 0
3 years ago
Determine the initial void ratio, the relative density and the unit weight (in pounds per cubic foot) of the specimens for each
Elina [12.6K]

The initial void ratio is the <em>parameter </em>which is used to show the structural foundations for each <em>specimen of sand </em>so that the method and speed of compression would be <em>measured</em>.

Relative density is the mass per unit volume of each specimen of sand which is <em>measured </em>and it has to do with the<em> relative ratio</em> of the density of the sand.

Unit weight is the the exact weight per cubic foot of the sand which is measured.

Please note that your question is incomplete so I gave you a general overview to help you better understand the concept

Read more here:

brainly.com/question/15220801

5 0
2 years ago
The output side of an ideal transformer has 35 turns, and supplies 2.0 A to a 24-W device. Ifthe input is a standard wall outlet
Crank

Answer:

The current drawn from the outlet is 0.2 A

The number of turns on the input side is 350 turns

Explanation:

Given;

number of turns of the secondary coil, Ns = 35 turns

the output current, I_s = 2 A

power supplied, P_s = 24 W

the standard wall outlet in most homes = 120 V = input voltage

For an ideal transformer; output power = input power

the current drawn from the outlet is calculated;

I_pV_p = P_s\\\\I_p = \frac{P_s}{V_p} = \frac{24}{120} = 0.2 \ A

The number of turns on the input side is calculated as;

\frac{N_p}{N_s} = \frac{I_s}{I_p}  \\\\N_p = \frac{N_sI_s}{I_p} \\\\N_p = \frac{35 \times 2}{0.2} \\\\N_p = 350 \ turns

4 0
3 years ago
What type of engineer works to create a practical and safe energy source?
Fittoniya [83]
Why did you put this on here when you know the answer lol
4 0
3 years ago
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