Classius claperyon equation
In (P2/ P2) = ΔHvap/R) × (1/T2-1/T1)
T2 occurs at normal boiling when vapor pressure P2 = 1 atm.
P1 = 55.1 mmHg, P2 = 1 atm = 760mmHg
T1 = 35°c = 308.15k, T2 =
ΔHvap = 32.1kJ/mol = 32100 J/mol
In (760/55.1) = (-32100/ 8.314) × ( 1/T2 - 1/308.15)
The normal boiling point T2 = 390k = 117°c
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We have that the magnitude of the gravitational force is mathematically given as
f=6.377N
<h3>
Force</h3>
Question Parameters:
Earth exerts a 100 N gravitational force on a metal box.
(Mass of the earth is 6e24 kg and radius of the earth is 6.4e6m.)
Generally the equation for the Gravitational mForce is mathematically given as

f=6.377N
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Answer:the
8/9 h
Explanation:
Height = 1/2 a T^2 now change to T/3
now height = 1/2 a (T/3)^2 =<u> 1/9</u> 1/2 a T^2 <===== it is 1/9 of the way down or 8/9 h