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Oksi-84 [34.3K]
3 years ago
10

A wave pulse traveling to the right along a thin cord reaches a discontinuity where the rope becomes thicker and heavier. What i

s the orientation of the reflected and transmitted pulses?
a) both are inverted

b) the reflected pulse returns inverted while the transmitted pulse is right side up

c) both are right side up

d) the reflected pulse returns right side up while the transmitted pulse is inverted
Physics
1 answer:
Tema [17]3 years ago
5 0

Answer:

b) the reflected pulse returns inverted while the transmitted pulse is right side up

Explanation:

A wave pulse traveling to the right along a thin cord reaches a discontinuity where the rope becomes thicker and heavier.

Then, as far as orientation of reflected and transmitted pulses are concerned the reflected pulse returns inverted while the transmitted pulse is right side up.

Hence the correct answer is b.

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If a cars velocity is slowing down is it considered a positive or negative acceleration?
Natali [406]

Answer:

Negative

Explanation:

Observe that the object below moves in the positive direction with a changing velocity. An object which moves in the positive direction has a positive velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion (in this case, a negative acceleration).

4 0
3 years ago
A long straight cylindrical shell has an inner radius R_i and an outer radius R_0. It carries a current i, uniformly distributed
Irina-Kira [14]

Answer:

Correct answer is option D

- Wire is on the cylinder axis and carries current i in the direction opposite to that of the current in the shell

Explanation:

- It cannot be Option E, because the magnetic field outside the wire would not be 0 due to the current carried by the conductor

-Also, the parallel wire cannot carry current in the same direction because, that would amplify the magnetic field created by the outer cylinder (since B is dir. proportional to the current) -and now, that leaves only option C and D. If, it is Option C, then that means one side of the cylinder would be more closer to the parallel wire than the other, so there would be different B fields on the two opposite sides of the cylinder. So, that means the answer is option D.

7 0
3 years ago
Calculate the work done by a force of 30 N in lifting a load of 2 kg to a height of 10 m (g = 10 m/s2)
Mars2501 [29]

Answer:

<u>300 J</u>

Explanation:

Given :

  1. Applied force = 30 N
  2. Mass = 2 kg
  3. Height = 10 m
  4. g = 10 m/s²

Work done by the force :

  • Work done = Force x Displacement
  • Work done = mg x h
  • Work done = 30 N x 10 m
  • Work done = <u>300 J</u>

<u></u>

<u><em>Note</em></u> :

  • What you have calculated is the work done by gravitational force on the object (that too, incorrectly)
  • But in the end, it asks for work done by the force of 30N
  • Hence, the given answer ~
3 0
2 years ago
HELP⚠️⚠️
alexgriva [62]

Answer:

I think u are traeling at speed of light and not ur friend

Explanation:

4 0
3 years ago
Read 2 more answers
A 1100 kg car starts from rest and accelerates for 5 seconds at 4.6m/s/s how much power does the car generate
SIZIF [17.4K]

Answer:

The power expended by the car during the acceleration is 116.38KW

Explanation:

Power is a term that defines the rate at which energy is expended whenever work is done.

Power can be given as Force X velocity.

Force can be found using the formula:

F = mass X acceleration.

In this case,

F = 1100kg X 4.6m/s2

F = 5060 N

The final velocity, v of the car can be obtained from this formula:

v = u+ at

U = initial velocity = 0 (since the car started from rest)

a = acceleration = 4.6m/s2

t = time = 5 seconds

v = 0 + 4.6 X 5 = 23 m/s

Therefore, the power expended is 5060N X 23m/s=116,380W

The power expended by the car during the acceleration is 116.38KW

3 0
3 years ago
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