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Oksi-84 [34.3K]
3 years ago
10

A wave pulse traveling to the right along a thin cord reaches a discontinuity where the rope becomes thicker and heavier. What i

s the orientation of the reflected and transmitted pulses?
a) both are inverted

b) the reflected pulse returns inverted while the transmitted pulse is right side up

c) both are right side up

d) the reflected pulse returns right side up while the transmitted pulse is inverted
Physics
1 answer:
Tema [17]3 years ago
5 0

Answer:

b) the reflected pulse returns inverted while the transmitted pulse is right side up

Explanation:

A wave pulse traveling to the right along a thin cord reaches a discontinuity where the rope becomes thicker and heavier.

Then, as far as orientation of reflected and transmitted pulses are concerned the reflected pulse returns inverted while the transmitted pulse is right side up.

Hence the correct answer is b.

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The wavelength of the wave is 1.16m and the velocity is 23.64m/s.

To find the answer, we have to know more about the Transverse waves.

<h3>How to find different parameters of a wave?</h3>
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                y(x,t)=0.048sin(5.40x-128t)

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               amplitude, a=0.048m\\wave vector, k=5.40\\angular frequency,w=128Hz

  • We have to find the wavelength of the wave, for this, we have the expression as,

                k=\frac{2\pi }{wavelength} \\\\wavelength=\frac{2\pi }{k} =\frac{2*3.14}{5.40} \\\\wavelength=1.16m

  • We have to find the velocity of the wave,

                         v=frequency*wavelength\\2\pi f=w, thus,\\f=\frac{w}{2\pi } =\frac{128}{2*3.14}=20.38s^{-1}\\\\v=1.16*20.38=23.64m/s

Thus, we can conclude that, the wavelength of the wave is 1.16m and the velocity is 23.64m/s

Learn more about the transvers waves here:

brainly.com/question/25746208

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If we approximate the orbit of the planets around the Sun to circular orbits with a uniform circular motion, where the velocity \vec{V} is a vector, whose direction is perpendicular to the radius r of the trajectory; the acceleration \vec{a} is directed towards the center of the circumference (that's why it's called centripetal acceleration).  

Now, according to Newton's 2nd law, the force \vec{F} is directly proportional and in the same direction as the acceleration:  

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Therefore the net force resulting from the movement of a planet orbiting the Sun points towards the center of the circle, this is called Centripetal Force which is a central force that in this case is equal to the gravity force.

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