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marusya05 [52]
3 years ago
6

What is the magnetic force on a proton that is moving at 5.2 x 10^7 m/s to the left through a magnetic field that is 2.4 T and p

ointing toward you? The charge on a proton is 1.6 x 10^-19 C.
A. 2.0 x 10^-11 N down
B. 2.0 x 10^-11 N up
C. 8.3 x 10^-12 N up
D. 8.3 x 10^-12 N down
Physics
1 answer:
Ivahew [28]3 years ago
3 0
The answer is A. 2.0 * 10^ -11N down
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A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 w
steposvetlana [31]

Explanation:

a) The height of the ball h with respect to the reference line is

h = L - L\cos{31°} = L(1 - \cos{31°})

so its initial gravitational potential energy U_0 is

U = mgh = mgL(1 - \cos{31°})

\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})

\:\:\:\:\:=0.23\:\text{J}

b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U

We know that the initial kinetic energy K_0, as well as its final gravitational potential energy U are zero so we can write the conservation law as

mgL(1 - \cos{31°}) = \frac{1}{2}mv^2

Note that the mass gets cancelled out and then we solve for the velocity v as

v = \sqrt{2gL(1 - \cos{31°})}

\:\:\:\:\:= \sqrt{2(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31°})}

\:\:\:\:\:= 1.3\:\text{m/s}

5 0
2 years ago
Read 2 more answers
5) What type of substance can seep<br> groundwater and make it unusable?
sergeinik [125]

Answer:

I believe <u>chemicals</u>, though I might be wrong.

Explanation:

7 0
2 years ago
The speed of a 180-g toy car at the bottom of a vertical circular portion of track is 7.75 m/s. If the radius of curvature of th
Bezzdna [24]

Answer:

11.28 N toward the center of the track

Explanation:

Centripetal force: This is the force that tend to draw a body close to the center of a circle, during circular motion.

The formula for centripetal force is given as,

F = mv²/r................................ Equation 1

Where F = force, m = mass of the toy car, v = velocity, r = radius

Given: m = 108 g = 0.108 kg, v = 7.75 m/s, r = 57.5 cm = 0.575 m

Substitute into equation 1

F = 0.108(7.75²)/0.575

F = 11.28 N

Hence the magnitude and direction of the force = 11.28 N toward the center of the track

7 0
3 years ago
Do you have a lawn mower engine running for 20 minutes does 4,560, 000 J of work. What is the power output of the engine?
alekssr [168]

Answer:

P = 3800 W

Explanation:

Power is equal to energy divide by time P = E/t

plug in 4560000 J for energy

convert 20 minutes to seconds

20 * 60 = 1200 seconds

plug in 1200 seconds for time

P = 4560000/1200

P = 3800 W

7 0
3 years ago
In the system illustrated by the diagram, the magnetic field is increasing. In which
Black_prince [1.1K]

The emf will be induced in anti-clockwise direction.

<u>Explanation</u>

Lenz's law tells us the direction us the direction that the current will flow. It states that the direction is always such that it will oppose the change in flux which produced it. This means that any magnetic field produced by an induced current will be in opposite direction to the change in the original field.

To find the direction of emf, Stretch the forefinger, middle finger and the thumb of the right hand mutually perpendicular to each other. If the force finger points in the direction of the magnetic field, the thumb gives the direction of the motion of the conductor then the middle finger gives the direction of the induced current.

3 0
3 years ago
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