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DerKrebs [107]
4 years ago
9

It would take almost 2 years for the fastest human-made spacecraft to travel from earth to europa. about how long would it take

such a spacecraft to travel to wolf 359? study island
Physics
1 answer:
worty [1.4K]4 years ago
4 0
First, we need the distance of Europe and Wolf-359 from Earth.
- The distance of Europe from Earth is: d_E = 6.28 \cdot 10^8 km
- The distance of Wolf-359 from Earth is instead 7.795 light years. However, we need to convert this number into km. 1 light year is the distance covered by the light in 1 year. Keeping in mind that the speed of light is c=3 \cdot 10^8 m/s, and that in 1 year there are 
365 days x 24 hours x 60 minutes x 60 seconds = 3.154 \cdot 10^7 s/y, the distance between Wolf-359 and Earth is
d_W = 7.995 ly\cdot3\cdot 10^8 m/s \cdot 3.154 \cdot 10^7 s=7.38 \cdot 10^{16}m=7.38 \cdot 10^{13}km

Now we can calculate the time the spaceship needs to go to Wolf-359, by writing a simple proportion. In fact, we know that the spaceship takes 2 years to cover d_E, so
2 y:d_E = x:d_W
from which we find x, the time needed to reach Wolf-359:
x= \frac{2 y\cdot d_W}{d_E}=2.35 \cdot 10^5 years
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3 years ago
A hockey puck on a frozen pond is given an initial speed of 20.0 m/s. If the puck always remains on the ice and slides 115 m bef
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Answer:

μ_k = 0.1773

Explanation:

We are given;

Initial velocity;u = 20 m/s

Final velocity;v = 0 m/s (since it comes to rest)

Distance before coming to rest;s = 115 m

Let's find the acceleration using Newton's second law of motion;

v² = u² + 2as

Making a the subject, we have;

a = (v² - u²)/2s

Plugging relevant values;

a = (0² - 20²)/(2 × 115)

a = -400/230

a = -1.739 m/s²

From the question, the only force acting on the puck in the x direction is the force of friction. Since friction always opposes motion, we see that:

F_k = −ma - - - (1)

We also know that F_k is defined by;

F_k = μ_k•N

Where;

μ_k is coefficient of kinetic friction

N is normal force which is (mg)

Since gravity acts in the negative direction, the normal force will be positive.

Thus;

F_k = μ_k•mg - - - (2)

where g is acceleration due to gravity.

Thus,equating equation 1 and 2,we have;

−ma = μ_k•mg

m will cancel out to give;

-a = μ_k•g

μ_k = -a/g

g has a constant value of 9.81 m/s², so;

μ_k = - (-1.739/9.81)

μ_k = 0.1773

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3 years ago
A stereo speaker is placed between two observers who are 35 m apart, along the line connecting them. If one observer records an
kompoz [17]

Answer:

   x = 2,864 m ,       Ra = 32.1 m                       

Explanation:

Let's solve this problem in parts, let's start by finding the intensity of the sound in each observer

observer A β = 64 db

             β = 10 log Iₐ / I₀

where I₀ = 1 10⁻¹² W / m²

              Iₐ = I₀ 10 (β/ 10)

let's calculate

              Iₐ = 1 10⁻¹² (64/10)

              Iₐ = 2.51 10⁻⁶ W / m²

Observer B β = 85 db

             I_b = 1 10-12 10 (85/10)

             I_b = 3.16 10⁻⁴ W / m²

now we use that the emitted power that is constant is the intensity over the area of ​​the sphere where the sound is distributed

              P = I A

therefore for the two observers

              P = Ia Aa = Ib Ab

the area of ​​a sphere is

               A = 4π R²

we substitute

               Ia 4pi Ra2 = Ib 4pi Rb2

               Ia Ra2 = Ib Rb2

Let us call the distance from the observer be to the haughty R = ax, so the distance from the observer A to the haughty is R = 35 ax; we substitute

             Ia (35 -x) 2 = Ib x2

we develop and solve

           35-x = Ra (Ib / Ia) x

           35 = [Ra (Ib / Ia) +1] x

           x (11.22 +1) = 35

           x = 35 / 12.22

            x = 2,864 m

This is the distance of observer B

The distance from observer A

            Ra = 35 - x

            Ra = 35 - 2,864

            Ra = 32.1 m

8 0
3 years ago
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