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Alexxx [7]
3 years ago
8

The picture shows rays passing through an unknown lens.

Physics
2 answers:
ValentinkaMS [17]3 years ago
6 0

Answer:

its D. D

Explanation:

Scrat [10]3 years ago
5 0

Answer:

I believe the answer is D on E2020. Hope this helps

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How would be best to find a scientific law? A) Generalized rule to explain a body of observations.
lord [1]

Answer:

In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory

5 0
3 years ago
The bodies in this universe attract one another name the scientist who propounded this statement​
murzikaleks [220]

Answer:

It was proposed by Isaac Newton

Explanation:

The law of universal attraction of expression

          F = G \ \frac{m_1m_2}{ r^2}G m1m2 / r ^ 2

where G is a constant, m₁ and m₂ are the masses of the bodies and r the distance between them.

It was proposed by Isaac Newton

With this law Newton explained that the force that pulls the moon towards the earth is the same as that which attracts an apple towards the earth

8 0
3 years ago
the freezing point of water is the same as ice's __________ point. a. boiling b. melting c. condensing d. sublimation
nika2105 [10]
Melting. Water freezes at 0 degrees celsius or 32 degrees fahrenheit and therefore water freezes at that temperature or ice melts back to its liquid state at those temperatures.
3 0
4 years ago
Answers please and thank you​
viktelen [127]

Answer:

W

Explanation:

its high in mass object and volume object

3 0
3 years ago
A positive point charge q1 = +5.00 × 10−4C is held at a fixed position. A small object with mass 4.00×10−3kg and charge q2 = −3.
Lelechka [254]

Answer:

Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.

Explanation:

Energy conservation law: In isolated system the amount of total energy remains constant.

The types of energy are

  1. Kinetic energy.
  2. Potential energy.

Kinetic energy =\frac{1}{2} mv^2

Potential energy =\frac{Kq_1q_2}{d}

Here, q₁= +5.00×10⁻⁴C

q₂=-3.00×10⁻⁴C

d= distance = 4.00 m

V = velocity = 800 m/s

Total energy(E) =Kinetic energy+Potential energy

                      =\frac{1}{2} mv^2+ \frac{Kq_1q_2}{d}

                     =\frac{1}{2} \times 4.00\times 10^{-3}\times(800)^2 +\frac{9\times10^9\times 5\times10^{-4}\times(-3\times10^{-4})}{4}

                    =(1280-337.5)J

                    =942.5 J

Total energy of a system remains constant.

Therefore,

E =\frac{1}{2} mv^2 + \frac{Kq_1q_2}{d}

\Rightarrow  942.5 = \frac{1}{2} \times 4 \times10^{-3} \times V^2 +\frac{9\times10^{9}\times5\times 10^{-4}\times(-3\times 10^{-4})}{0.2}

\Rightarrow 942.5 = 2\times10^{-3}v^2 -6750

\Rightarrow 2 \times10^{-3}\times v^2= 942.5+6750

\Rightarrow v^2 = \frac{7692.5}{2\times 10^{-3}}

\Rightarrow v= 1961.19   m/s

Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.

5 0
3 years ago
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