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ss7ja [257]
3 years ago
5

Decribe what makes a diamand a mineral

Physics
1 answer:
RUDIKE [14]3 years ago
7 0
Very very very high pressures, very etc high temperatures, varying degrees of "carbon purity"  and a long time make diamonds diamonds. Minerals ? Well, every so often, should you be lucky, or live in South Africa you might come across one. (Let me know if you do).
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PLEASE HELP MEE I REALLY NEED IT
nignag [31]

Answer:

measures of central tendency are numbers that describe what an average or typical within a distribution of data there are three main measures of central tendency mean medium and mold well they are all measuring essential tendency each is calculated differently and measures something different from others

5 0
3 years ago
5. If Joe spend 250 W power to lift a box weighing 25.5 kg in 3.0 s, how high did he lift the box?
Serjik [45]

Answer:

3m

Explanation:

p=250w

m=25.5

t=3.0s

D=x

F=mxa   F= 25.5kg x 9.8m/s^2 =250N

D= 250wx3.0s/250w

3m

5 0
3 years ago
If two bodies weighing 10 kg and 20 kg respectively are standing at the
kvv77 [185]

Answer:

potential energy = mgh , where m is mass of body , g is acceleration due to gravity and h is given height

since both of the body are at same height above the ground , so the body having greater mass will have more potential energy

that is 20 kg body will have higher P.E

Explanation:

7 0
4 years ago
Why the specific heat capacity of the sun remain constant<br><br>​
gayaneshka [121]
The heat remains constant because there’s nothing to cool it down
7 0
3 years ago
an athlete runs 300 m up a hill at a steady speed of 3.0 m/s. She then immediately runs the same distance at 6.0 m/s . What is h
mina [271]

Answer:

4.0 m/s

Explanation:

In the first part of the run, the athlete runs a distance of

d_1 = 300 m

at a speed of

v_1 = 3.0 m/s

So, the time he/she takes is

t_1 = \frac{d_1}{v_1}=\frac{300}{3.0}=100 s

In the second part of the run, the athlete covers an additional distance of

d_2 = 300 m

with a speed

v_2 = 6.0 m/s

So, the time taken in this second part is

t_2 = \frac{d_2}{v_2}=\frac{300}{6.0}=50 s

So, the total distance covered is

d = 300 m + 300 m = 600 m

And the total time taken

t = 100 s + 50 s = 150 s

Therefore, the average speed for the entire trip is

v=\frac{d}{t}=\frac{600}{150}=4.0 m/s

4 0
4 years ago
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