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2 years ago

7.602x1024 atoms of lead has a mass of ____________ grams.

Chemistry

1 answer:

crimeas [40]2 years ago

7 0

Hello!

To find the mass of 7.602 x 10^24 atoms of lead, we need to find the number of moles first, then we will be able to find the mass. To find the moles, we need to divide the total number of atoms by Avogadro's number, which is 6.02 x 10^23. Also, one mole of lead is equal to it's atomic mass, which is 207.2 grams.

1). Find the number of moles

(7.602 x 10^24) / (6.02 x 10^23) ≈ 12.62790

Using significant figures, there are 12.8 moles of lead.

2). Find the mass of lead

12.8 moles x 207.2 grams = 2652.16 grams

Using significant figures, the mass of the given amount of lead is 2650 grams. (Exact value is 2652.16 grams).

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Answer:

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Explanation:

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Putting values in above equation, we get:

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according to reaction 1 mol of NaCl gives 1 mol of AgCl.

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$\frac{1}{1}\times 0.02495 mol=0.02495 mol$ of AgCl

Mass of 0.02495 moles of AgCl:

$0.02495 mol\times 143.5 g/mol=3.5803 g$

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