What type of soil is found around Pennsylvania riverbanks and consists of particles smaller than sand

Bone has a Young’s modulus of about

Softa [21]

Answer:

4.25 mm

Explanation:

σ = E ∙ ∆L/L₀

where σ is stress,

E is Young's modulus,

and ∆L/L₀ is strain (∆L is the deflection, L₀ is the initial length).

Plugging in values:

1.53×10⁸ Pa = (1.8×10¹⁰ Pa) ∆L / (500 mm)

∆L = 4.25 mm

5 0

4 years ago

A lens is used to make an image of magnification -1.50. The image is 30.0 cm from the lens. What is the object’s distance (unit=

photoshop1234 [79]

Answer:

The object distance is 20cm

Explanation:

Given

Magnification = -1.5

Image distance = 30 cm.

Required

Object Distance

We can calculate the object's distance using magnification formula;

M = -V/U

Where M = Magnification = -1.50

V = Image Distance = 30cm

U = Object Distance

Substitute the above parameters in the formula above.

-1.50 = -30/U

Multiply both sides by -1

-1.50 * -1 = -30/U * -1

1.50 = 30/U

Multiply both sides by U

1.50 * U = 30/U * U

1.50U = 30

Divide through by 1.50

1.50U/1.50 = 30/1.50

U = 30/1.50

U = 20cm

Recall that U represented the object distance.

Hence, the object distance is 20cm

5 0

4 years ago

Explain why the moon is always half illuminated and half dark no matter where it is in the lunar cycle.

BlackZzzverrR [31]

The easiest way I know to explain it is this:

-- Take a flashlight and a ball into a dark room.

-- Turn on the flashlight and point it at the ball.

-- Half of the ball is lighted up by the flashlight, and the other half is dark.

-- There is no way you can turn or twist the ball to make more or less
than 50% of it lighted up and more or less than 50% of it dark.

<em>Everything</em> in the solar system ... as long as it's shaped like a ball ... is
half illuminated by the sun and half dark.

7 0

3 years ago

An object initially at rest experiences an acceleration of 9.8 m/s2 how much time will it take it to achieve a velocity of 58 m/

Ber [7]

Answer:

The time required by object to achieve velocity 58 m/s is 5.918 second.

Given:

acceleration = 9.8 $\frac{m}{s^{2} }$

Initial velocity = 0 m/s

final velocity = 58 m/s

To find:

Time required by object = ?

Formula used:

According to first equation of motion is given by,

v = u + at

Where, v = final velocity

u = initial velocity = 0 (Given The particle is at rest initially)

a = acceleration

t = time

Solution:

According to first equation of motion is given by,

v = u + at

Where, v = final velocity

u = initial velocity = 0 (Given The particle is at rest initially)

a = acceleration

t = time

58 = 0 + 9.8 (t)

t = $\frac{58}{9.8}$

t = 5.918 s

The time required by object to achieve velocity 58 m/s is 5.918 second.

8 0

4 years ago

A block is at rest on the incline shown in the gure. The coefficients of static and kinetic friction are 0.6 and 0.51, respec- t

Alekssandra [29.7K]

Normal reaction force on the block while it is at rest on the inclined plane is given as

$F_n = mgcos\theta$

here we know that

m = 46 kg

$\theta = 29^o$

now we will have

$F_n = 46*9.8*cos29 = 394.3 N$

now the limiting friction or maximum value of static friction on the block will be given as

$F_s = \mu_s * F_n$

$F_s = 0.6 * 394.3 = 236.56 N$

Above value is the maximum value of force at which block will not slide

Now the weight of the block which is parallel to inclined plane is given as

$F_{||} = mg sin\theta$

here we know that

$F_{||} = 46*9.8 sin29 = 218.55 N$

Now since the weight of the block here is less than the value of limiting friction force and also the block is at rest then the frictional force on the block is static friction and it will just counter balance the weight of the block along the inclined plane.

So here <u>friction force on the given block will be same as its component on weight which is 218.55 N</u>

5 0

3 years ago