Answer:
25 m/s
Explanation:
First we should define the variables
T=4
Dx = 100
ay=-9.8
ax=0
We can use formula 1 from the BIG 5
x=(v+v0)t/2
By plugging in our variables we can get 100=4(v+v0)/2
Which is 50=v+v0
v=v0 since horizontal acceleration always equals zero
so 2v0 = 50
v0 = 25
Initial speed is less than final speed
The average speed would be 33.29m/s.The average speed equation is:
![Average speed = \frac{total distance}{total time}](https://tex.z-dn.net/?f=Average%20speed%20%3D%20%20%5Cfrac%7Btotal%20distance%7D%7Btotal%20time%7D%20)
First you will need to solve for the distance you traveled in each scenario. So we can solve this by getting the product of speed and the time traveled.
Scenario 1:
Speed = 29m/s
Time = 120s
Distance = ?
Distance = (29m/s)(120s)
= 3,480m
Scenario 2
Speed = 35m/s
Time = 300s
Distance = ?
Distance = (35m/s)(300s)
= 10,500m
Now that you have the distance of both, you can solve for your average speed.
Answer:
Speed changes at the rate of 24 m/s for each second over time.
Explanation:
We are told the object's acceleration is equal to 24 m/s²
Now we know that acceleration can also be defined as the rate of change of speed with time. Also speed has a unit known as m/s.
Thus, we can rephrase the acceleration in this question to mean;
Speed changes at the rate of 24 m/s for every second with time.