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2 years ago

8

- Make Sense and Persevere If x represents the number

1 answer:

stealth61 [152]2 years ago

3 0

Answer:

5,46 inches per months

Step-by-step explanation:

1 year = 12 months

The average precipitation per month is :

65,52 inches ÷ 12 = 5,46 inches per months

HOPE THIS HELPED ;3

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Explain how the distance formula can prove Pythagoras' Theorem. In your

Paul [167]

Answer:

Given a triangle ABC, Pythagoras' Theorem shows that:

$c^2=a^2+b^2$

Thus,

$c = \sqrt{a^2+b^2}$

The distance formula, gives an equivalent expression based on two points at the end of the hypotenuse for a triangle.

$d^2 = (x_{2} -x_{1})^2 + (y_{2} -y_{1})^2$

$d = \sqrt{(x_{2}-x_{1})^2 + (y_{2} -y_{1})^2 }$

Therefore when given the hypotenuse with endpoints at

$(x_{1}, y_{1}) and {(x_{2}, y_{2})$

We know that the third point of the right triangle will be at

$(x_{2}, y_{1})$

and that the two side lengths will be defined by the absolute values of:

$(x_{2} - x_{1}) = a$

$(y_{2} - y_{1}) = b$

8 0

2 years ago

Last year the dept of the river was 4.2 feet deep. THIS YEAR UT DROPPED 11% find the depth of the f the river this year

Romashka [77]

Answer:

new depth =

4.2/100 X 89 = 3.738 feet

4 0

2 years ago

How do I solve the equation m+15=-22

MariettaO [177]

$m+15=-22$

$15m=-22-15
$

$m=-37$

7 0

2 years ago

Read 2 more answers

Solve the following quadratic by<br> completing the square.<br> y = x^2 - 6x+7

kozerog [31]

Answer:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

Step-by-step explanation:

<u>Given quadratic equation</u>:

$y = x^2 - 6x+7$

To complete the square, begin by adding and subtracting the square of half the coefficient of the term in x:

$\implies y = x^2 - 6x+\left(\dfrac{-6}{2}\right)^2-\left(\dfrac{-6}{2}\right)^2+7$

$\implies y = x^2 - 6x+\left(-3\right)^2-\left(-3\right)^2+7$

$\implies y = x^2 - 6x+9-9+7$

Factor the perfect square trinomial:

$\implies y=(x-3)^2-9+7$

$\implies y=(x-3)^2-2$

To solve the quadratic, set it to zero and solve for x:

$\implies (x-3)^2-2=0$

$\implies (x-3)^2-2+2=0+2$

$\implies (x-3)^2=2$

$\implies \sqrt{(x-3)^2}=\sqrt{2}$

$\implies x-3= \pm\sqrt{2}$

$\implies x-3+3= 3\pm\sqrt{2}$

$\implies x= 3\pm\sqrt{2}$

Therefore, the solution to the given quadratic equation is:

$x= 3+\sqrt{2}, \quad x= 3 -\sqrt{2}$

6 0

7 months ago

Read 2 more answers

Long division 12p^5+20p^4+18p^2+45p+25/3p+5

lina2011 [118]

Answer:

$4p^4+6p+5$

Step-by-step explanation:

Given

$\frac{12p^5+20p^4+18p^2+45^p+25}{3p+5}$

Step 1:

Now Dividing the above Equation our first quotient will be $4p^4$ and First remainder will be $18p^2+45p$

Step 2:

Now Dividing the First remainder $18p^2+45p$ with $3p+5$

now our second Quotient will be $4p^4+6p$ and Second remainder will be $15p+25$

Step 3:

Now Dividing Second remainder $15p+25$ with $3p+5$

now our third Quotient will be $4p^4+6p +5$ and Remainder will be 0.

$\therefore$ Our Final Answer is $4p^4+6p +5$ with remainder 0

4 0

2 years ago