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Jlenok [28]
3 years ago
15

16. Predict how the wavelength and frequency of a wave would change if the amount of energy it carried was increased.

Chemistry
2 answers:
pishuonlain [190]3 years ago
5 0

Answer:

1.- The energy of a wave will increase the frequency due to the increase in the speed of the wave.

2.- The wavelength will increase if the energy of the wave increases, due to the area that is expand.

3.- A wave with a higher frequency will have faster speed to move.

Explanation:

Wavelength of a wave is due to the speed and the energy that the wavelength carry, so if the energy increases, this quantity of energy need to distribute or in the wavelength or in the frequency, to conduct the wave with a bigger amount of energy.

Lostsunrise [7]3 years ago
3 0

Explanation:

Frequency is related to the energy carried by the wave, the higher the energy  the faster it oscilates and the higher the frequency. The wavelenght is the distance between two consecutive valleys of a wave. It's inversely proportional to the frequency, therefore if the frequency increases with the energy, the wavelength decreases.

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5.943x10^24 molecules of H3PO4 will need how many grams of Mg(OH)2 in the reaction below? 3 Mg(OH)2 + 2 H3PO4 -------> 1 Mg3(
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Answer:

Mass of Mg(OH)₂ required for the reaction = 863.13 g

Explanation:

3Mg(OH)₂ + 2H₃PO₄ -------> Mg₃(PO₄)₂ + 6H₂O

(5.943 x 10²⁴) molecules of H₃PO₄ is available fore reaction. Mass of Mg(OH)₂ required for reaction.

According to Avogadro's theory, 1 mole of all substances contain (6.022 × 10²³) molecules.

This can allow us find the number of moles that (5.943 x 10²⁴) molecules of H₃PO₄ represents.

1 mole = (6.022 × 10²³) molecules.

x mole = (5.943 x 10²⁴) molecules

x = (5.943 x 10²⁴) ÷ (6.022 × 10²³)

x = 9.87 moles

From the stoichiometric balance of the reaction,

2 moles of H₃PO₄ reacts with 3 moles of Mg(OH)₂

9.87 moles of H₃PO₄ will react with y moles of Mg(OH)₂

y = (3×9.87)/2 = 14.80 moles

So, 14.8 moles of Mg(OH)₂ is required for this reaction. We them convert this to mass

Mass = (number of moles) × Molar mass

Molar mass of Mg(OH)₂ = 58.3197 g/mol

Mass of Mg(OH)₂ required for the reaction

= 14.8 × 58.3197 = 863.13 g

Hope this Helps!!!

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