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g100num [7]
2 years ago
7

Which of the following is true? All statements are false A basic solution does not contain H3O+ A neutral solution contains [H2O

] = [H3O+] A neutral solution does not contain any H3O+ or OH- An acidic solution has [H3O+] > [OH-]
Chemistry
2 answers:
miv72 [106K]2 years ago
5 0

Answer:

An acidic solution has [H3O+] > [OH-]

Explanation:

Hydronium ions (H+ or H3O+) are acidic ions while hydroxide ions (OH–) are basic ions

choli [55]2 years ago
3 0

Answer:

An acidic solution has [H3O+] > [OH-]

Explanation:

A basic solution are substances that, in aqueous solution, release hydroxide (OH−) ions that is it contains more OH- than H3O+ in an aqueous solution while an acidic solution are substances that, in aqueous solution, release hydroxide H3O+ ions.

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How many electrons does nitrogen (N) need to gain to have a stable outer electron shell
earnstyle [38]
It need "3 electrons" to have a stable electronic configuration. 

'cause it has 5 electrons in it's outer shell & every atom needs 8 electrons. So, it requires 3 more!

Hope this helps!
7 0
2 years ago
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Question 3) A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in LiF. Calculate the pH of the solution after the addition of
Masja [62]

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

<u>Explanation:</u>

We have the chemical equation,

HF (aq)+NaOH(aq)->NaF(aq)+H2O

To find how many moles have been used in this

c= n/V=> n= c.V

nHF=0.250 M⋅1.5 L=0.375 moles HF

Simillarly

nF=0.250 M⋅1.5 L=0.375 moles F

nHF=0.375 moles - 0.250 moles=0.125 moles

nF=0.375 moles+0.250 moles=0.625 moles

[HF]=0.125 moles/1.5 L=0.0834 M

[F−]=0.625 moles/1.5 L=0.4167 M

To determine the problem using the Henderson - Hasselbalch equation

pH=pKa+log ([conjugate base/[weak acid])

Find the value of Ka

pKa=−log(Ka)

pH=−log(Ka) +log([F−]/[HF]

pH= -log(3.5 x 10 ^4)+log(0.4167 M/0.0834 M)

pH=-log(3.5 x 10 ^4)+log(4.996)

pH= -4.54+0.698

pH=-(-3.84)

pH=3.84

The pH of the solution after adding 0.150 moles of solid LiF is 3.84

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3 years ago
What is the birds and the bees
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2 years ago
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If you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of
irakobra [83]

Answer:

0.22

Explanation:

Given, Mass of C_{18}H_{21}NO_3 = 46.85 g

Molar mass of C_{18}H_{21}NO_3 = 299.4 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{46.85\ g}{299.4\ g/mol}

Moles\ of\ C_{18}H_{21}NO_3= 0.1565\ mol

Given, Mass of C_{2}H_{5}OH = 125.5 g

Molar mass of C_{2}H_{5}OH = 46.07 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{125.5\ g}{46.07\ g/mol}

Moles\ of\ C_{2}H_{5}OH= 0.5535\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ codeine=\frac {n_{codeine}}{n_{codeine}+n_{ethanol}}

Mole\ fraction\ of\ codeine=\frac{0.1565}{0.1565+0.5535}=0.22

4 0
3 years ago
Complete the balanced dissociation equation Cs2CO3
MaRussiya [10]

The balanced dissociation equation for Cs₂CO₃ is:

Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)

A dissociation equation is an equation showing the available ions present in a solution.

To obtain the dissociation equation, the compound must be dissolved in water to produce an aqueous solution.

The dissociation equation for Cs₂CO₃ can be written as follow

Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)

Learn more about dissociation equation: brainly.com/question/1903354

3 0
2 years ago
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