Answer:
what do you need help with? Like which type of print each image is?
Explanation:
Answer:
Impulse = 322.5[kg*m/s], the answer is D
Explanation:
This method it is based on the principle of momentum and the amount of movement; and used to solve problems involving strength, mass, speed and time.
If units of the SI are used, the magnitude of the impulse of a force is expressed in N * s. however, when remembering the definition of the newton.

Now replacing the values on the following equation that express the definition of impulse
![Impulse = Force * Time\\\\Impulse = 215 * 1.5 = 322.5 [kg*m/s]](https://tex.z-dn.net/?f=Impulse%20%3D%20Force%20%2A%20Time%5C%5C%5C%5CImpulse%20%3D%20215%20%2A%201.5%20%3D%20322.5%20%5Bkg%2Am%2Fs%5D)
Answer:
0.004 m
Explanation:
For light passing through a single slit, the position of the nth-minimum in the diffraction pattern is given by

where
is the wavelength
D is the distance of the screen from the slit
d is the width of the slit
Therefore, the width of the central maximum is equal to twice the value of y for n=1 (first minimum):

where we have
is the wavelength
D = 2.0 m is the distance of the screen
is the width of the slit
Substituting, we find

Answer:
Fr = 20 (N)
Explanation: See atached file ( free body diagram)
As for Newton´s low
∑ Fy = 0
-mg + N = 0 ⇒ - 40 + N = 0 ⇒ N = 40 [Newtons]
by definition : Fr = μs * N ⇒ Fr = 0,5 * 40 ⇒ Fr = 20 (N)
∑ Fx = 0 body is at rest
Fe - Fr = 0
Fr > Fe
Fr > 12 (N) the body is at rest