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Serjik [45]
3 years ago
6

Which SI unit is appropriate for measuring the height of a person?

Chemistry
1 answer:
lutik1710 [3]3 years ago
5 0
Para medir uma pessoa é necessario valor em METROS!!
espero ter ajudado!! ; )
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We start with the molecule below instead of palmitic acid, which step will be interrupted and which enzyme will be used to corre
zepelin [54]

Answer: Step 1, Isomerase.

Explanation:

Form the version of palmitic acid in the step one by changing the double bond within alpha and beta carbon by Isomerase.

B and C are Isomers, the molecule only differ in configuration.

4 0
3 years ago
Most metals are solid at room temperature Malibu ductile good conductors of heat and electricity and reacting to produce hydroge
kondaur [170]
Reacting to produce hydrogen gas is a chemical property
8 0
3 years ago
A 0.4272 g sample of an element contains 2.241 x 10 ^21 atoms . what is the symbol of the element?
grin007 [14]

Answer:

Likely \rm In (indium.)

Explanation:

Number of atoms: N = 2.241 \times 10^{21}.

Dividing, N, the number of atoms by the Avogadro constant, N_A \approx 6.023 \times 10^{23} \; \rm mol^{-1}, would give the number of moles of atoms in this sample:

\begin{aligned} n &= \frac{N}{N_{A}} \\ &\approx \frac{2.241 \times 10^{21}}{6.023 \times 10^{23}\; \rm mol^{-1}} \approx 3.72 \times 10^{-3}\; \rm mol \end{aligned}.

The mass of that many atom is m = 0.4272\; \rm g. Estimate the average mass of one mole of atoms in this sample:

\begin{aligned}M &= \frac{m}{n} \\ &\approx \frac{0.4272\; \rm g}{3.72 \times 10^{-3}\; \rm mol} \approx 114.82\; \rm g \cdot mol^{-1}\end{aligned}.

The average mass of one mole of atoms of an element (114.82\; \rm g \cdot mol^{-1} in this example) is numerically equal to the average atomic mass of that element. Refer to a modern periodic table and look for the element with average atomic mass 114.82. Indium, \rm In, is the closest match.

5 0
3 years ago
Help me answer this chemistry question. thank you!
tatiyna

Answer:

78.85

Explanation:

To <u>calculate the average atomic mass of the isotopes </u>we use the <em>given masses and abundances</em>, as follows:

  • Mass of Isotope 1 * Abundance of Isotope 1 + Mass of Isotope 2 * Abundance of Isotope 2 + ....

In other words:

  • 78 amu * 75/100 + 81 amu * 15/100 + 82 amu * 10/100 = 78.85

So the answer is 78.85.

8 0
3 years ago
Need a little help with chemistry:) <br> *if you don’t know don’t put anything*
Citrus2011 [14]

Answer:

its 1151000 grams teehee. ;)

4 0
3 years ago
Read 2 more answers
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