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3 years ago

Which figure represents the electric field lines of two negative point charges? Help

Physics

1 answer:

Yuliya22 [10]3 years ago

3 0

Answer:

The question is incomplete because the options are not given. We'll solve this question with the options.

There are two properties of negative charges which we have to consider to find the figure of its electrical field.

Firstly, for a negative charge, the electrical field lines are always directed radially outwards and they don't intersect.

Secondly, we know that similar charges repel each other, so there will be no electrical field present directly between these two negative charges. Electrical field line will be present between two charges only when there is a force of attraction.

Taking both of these facts into consideration, the electrical field line between two negatives is represented by the figure below.

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What is the magnetic flux linkage, in units of Weber, for a coil of 360 turns and cross sectional area of 0.133 m^2 when the mag

zalisa [80]

Answer:

83.3 Wb

Explanation:

The magnetic flux linkage through the coil is given by:

$N\phi = BAN sin \theta$

where

B is the magnetic field strength

A is the cross sectional area

N is the number of turns in the coil

$\theta$ is the angle between the direction of the field and the normal to the coil

In this problem:

B = 1.74 T

A = 0.133 m^2

N = 360

$\theta=90^{\circ}$

Therefore, the magnetic flux linkage is

$N\phi = (1.74 T)(0.133 m^2)(360) sin 90^{\circ}=83.3 Wb$

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3 years ago

Example 7.3

marysya [2.9K]

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A computer is connected across a 110 V power supply. The computer dissipates 123 W of power in the form of electromagnetic radia

nexus9112 [7]

Answer:

81.3ohms

Explanation:

Resistance is known to provide opposition to the flow of electric current in an electric circuit.

Power dissipated by the computer is expressed as;

Power = current (I) × Voltage(V)

P = IV... (1)

Note that from ohms law, V = IR

I = V/R ... (2)

Substituting equation 2 into 1, we will have;

P = (V/R)×V

P = V²/R.. (3)

Given source voltage = 100V, Power dissipated = 123W

To get resistance R of the computer, we will substitute the given value into equation 3 to have

123 = 100²/R

R = 100²/123

R = 10,000/123

R = 81.3ohms

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3 years ago