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Andrews [41]
3 years ago
7

Which substance in the reaction is considered to be the acid? A) HNO3 B) H2O C) NO3- D) H3O+

Chemistry
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

A (HNO3)

Explanation:

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Would magnesium prefer to lose or gain electrons
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Umm what kind of question is that but i think gain lol
8 0
3 years ago
How many moles of calcium carbonate-CaCO3 = 4.15 g​
marin [14]

Answer:

Number of moles = 0.042 mol

Explanation:

Given data:

Number of moles = ?

Mass of calcium carbonate = ?

Solution:

Formula:

Number of moles = mass/ molar mass

now we will calculate the molar mass of calcium carbonate.

atomic mass of Ca = 40 amu

atomic mass of C = 12 amu

atomic mass of O = 16 amu

CaCO₃ = 40 + 12+ 3×16

CaCO₃ = 40 + 12+48

CaCO₃ = 100 g/mol

Now we will calculate the number of moles.

Number of moles = 4.15 g / 100 g/mol

Number of moles = 0.042 mol

3 0
3 years ago
Different microscopic organisms cause different
lozanna [386]

Answer/Explanation:

A theory has lots of scientific evidence to back it up. We know this to be true based on lots of different diseases and studies of their spread.

A hypothesis is more of a starting point - an educated guess based on limited evidence. It requires further testing before becoming a theory.

A law is something that can be generalized to lots of contexts, and is universal. Such as the law of thermodynamics.

5 0
3 years ago
For a specific enzyme/substrate system, which condition will always result in an increase in Vo (assuming nothing else changes)?
inessss [21]
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8 0
3 years ago
A hot air balloon can have a volume of 2950 cubic meters (2.95 ✕ 106 liters) and operate at temperatures up to 250°F (121°C). As
TiliK225 [7]

Answer:

2.64 × 10⁶ g

Explanation:

We can find the mass of air using the ideal gas equation.

P.V=n.R.T=\frac{m}{M} .R.T

where,

P is the pressure (P = 1.00 atm)

V is the volume (V = 2.95 × 10⁶ L)

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (121°C + 273 = 394 K)

m is the mass

M is the molar mass (28.09 g/mol)

m=\frac{P.V.M}{R.T} =\frac{1.00atm \times 2.95 \times 10^{6} L \times 28.97g/mol}{(0.08206atm.L/mol.K) \times 394 K } =2.64 \times 10^{6} g

7 0
3 years ago
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