Answer:
1.0MG
Explanation:
to solve this problem we use this formula
S₀-S/t = ksx --- (1)
the values have been given as
concentration = S₀ = 250mg
effluent concentration = S= 10mg
value of K = 0.04L/day
x = 3000 mg
when we put these values into this equation,
250-10/t = 0.04x10x3000
240/t = 1200
we cross multiply from this stage
240 = 1200t
t = 240/1200
t = 0.2
remember the question says that 5MGD is required to be treated
so the volume would be
v = 0.2x5
= 1.0 MG
Answer:
The module is why it’s goin to work
Explanation:
Answer:
i dont know but i will take the points tho hahah
Explanation:
Answer:
(a) BP = 11.99 KPa
(b) h = 2 m
Explanation:
(a)
Since, the fluid pressure and blood pressure balance each other. Therefore:
BP = ρgh
where,
BP = Blood Pressure
ρ = density of fluid = 1020 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = height of fluid = 1.2 m
Therefore,
BP = (1020 kg/m³)(9.8 m/s²)(1.2 m)
<u>BP = 11995.2 Pa = 11.99 KPa</u>
(b)
Again using the equation:
P = ρgh
with data:
P = Gauge Pressure = 20 KPa = 20000 Pa
ρ = density of fluid = 1020 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = height of fluid = ?
Therefore,
20000 Pa = (1020 kg/m³)(9.8 m/s²)h
<u>h = 2 m</u>