Complete Question:
Find the capacitive reactance of a 0.1 microfarad capacitor with frequency 50Hz and at 200Hz.
Answer:
I. Capacitive reactance = 31826.86 Ohms.
II. Capacitive reactance = 7956.72 Ohms.
Explanation:
<u>Given the following data;</u>
Capacitance = 0.1 uF = 0.0000001 Farad
Frequency = 50 Hz and 200 Hz
To find the capacitive reactance;
Mathematically, the capacitive reactance of an electronic circuit is given by the formula;
Where;
- Xc is capacitive reactance.
- f is the frequency.
- c is the capacitance.
Substituting into the formula, we have;
I. At frequency, f = 50 Hz
II. At frequency, f = 200 Hz
Answer:
a) The minimum acceptable value is 387.5 HV using Vickers hardness test.
b) The minimum acceptable value is 39.4 HRC using Rockwell C hardness test.
Explanation:
To get the tensile strength of a material from its hardness, we multiply it by an empirical constant that depends on things like yield strength, work-hardening, Poisson's ratio and geometrical factors. The incidence of cold-work varies this relationship.
According to DIN 50150 (a conversion table for hardness), the constant for Vickers hardness is ≈ 3.2 (an empirical approximate):
According to DIN 50150, the constant for Rockwell C hardness test is ≈31.5 around this values of tensile strength:
Answer:
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