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3 years ago

6.3.9 A coin was tossed n = 1000 times, and the proportion of heads observed was

Engineering

1 answer:

4vir4ik [10]3 years ago

4 0

Answer:

Explanation:

51 / 100 = 510 / 1000

Chance of getting a head is 1 / 2 of total throws

= 1 / 2 × 1000

= 500 is the probability

and the number of heads was just 10 more the the probability...if the was a greater gap, there would be evidence to say the coin is unfair

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1. Using a typical frequency value for the initiating event and PFD values provided in class lectures, estimate the mishap or co

algol13

Answer:

a basic process control system is necessary as long as the work by the personnel in charge is efficient, this reduces by 90% the errors or failures to calculate the system to operate

Explanation:

Production staff human error

Another reason why a breakdown can occur is due to an error of the production personnel. This error, in turn, can originate from:

Error of interpretation of an indicator during the normal operation of the equipment, which causes the operator or driver of the installation to make the wrong decision

Incorrect performance in the event of a machine failure. For example, introducing water into a hot boiler in which water has been lost visually; as it is not known how much water is inside, it may be empty and hot, so when water is introduced it will produce instant vaporization, with the consequent increase in pressure that can even cause the boiler to explode.

Physical factors of the operator: this may not be in perfect condition to carry out his work, due to dizziness, sleep, fatigue accumulated by long working hours, illness, etc.

Psychological factors, such as demotivation, problems external to work, etc., greatly influence the proliferation of operational errors

Lack of clear systematic instructions, such as procedures, technical instructions, etc., or poor implementation of these Lack of training

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3 years ago

A two-stroke CI. engine delivers 5000 kWwhile using 1000 kW to overcome friction losses. It consumes 2300 kg of fuel per hour at

Lady_Fox [76]

Answer:

(a) Indicating power(IP)=6000 KW

(b) $\eta_{mech}$ =0.833

(d) $\eta_{BPth}$ =0.1865

Explanation:

Break power(BP) =5000 KW

Friction power(FP)=1000 KW

Consumption of fuel per hour=2300 kg/hr

CV=42000 KJ/kg

We know that

Indicating power(IP)=Break power(BP)+Friction power(FP)

⇒IP=5000+1000 KW

IP=6000 KW

(a)

Indicating power(IP)=6000 KW

(b)

Mechanical efficiency $\eta_{mech}=\dfrac{BP}{IP}$

$\eta_{mech}=\dfrac{5000}{6000}$

$\eta_{mech}$ =0.833

(c)

Air fuel ratio= $\dfrac{mass \ of \ air}{mass \ of \ fuel}$

consumption of air per hour=20 $\times$ 2300 kg/hr

So consumption of air per hour =46000 kg/hr

(d)

Break thermal efficiency $\eta_{BPth}=\dfrac{IP}{\dot{m_f}\times CV}$

$\dot{m_f}=\dfrac{2300}{3600}$

=0.638 kg/s

$\eta_{BPth}=\dfrac{5000}{{0.638}\times 42000}$

$\eta_{BPth}$ =0.1865

5 0

3 years ago

Draw the free-body diagram of the beam which supports the 80-kg load and is supported by the

Sauron [17]

The free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

The first image shows the diagram of the beam and the second image shows the free-body diagram of the beam.

The resolution of forces in the system is well understood by the principle of equilibrium where a stationary body will remain balanced when subject to parallel forces provided that the total sum of the overall external forces is zero.

The free-body diagram is a graphical representation used to visualize the forces applied to an object.

The equilibrium of forces on the x-axis is:

$\mathbf{\sum F_x = 0}$

The equilibrium of forces on the y-axis is:

$\mathbf{\sum F_y = 0}$

The equilibrium condition at any point is:

$\mathbf{\sum M = 0}$

From the free body diagram attached in the second image below,

the horizontal reaction is located at point A as $\mathbf{ A_x}$
the vertical reaction is located at point A as $\mathbf{A_y}$
the tension = T
the weight = W

Therefore, we can conclude that the free-body diagram of the beam which supports the 80-kg load and is supported by the pin at A can be seen in the image attached below.

Learn more about the free-body diagram here:

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