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il63 [147K]
3 years ago
7

Can you determine the critical distance along a flat surface?

Engineering
1 answer:
Keith_Richards [23]3 years ago
6 0

Explanation:

Consider a fluid of density, ρ moving with a velocity, U over a flat plate of length, L.

Let the Kinematic viscosity of the fluid be ν.

Let the flow over the fluid be laminar for a distance x from the leading edge.

Now this distance is called the critical distance.

Therefore, for a laminar flow, the critical distance can be defined as the distance from the leading edge of the plate where the Reynolds number is equal to 5 x 10^{5}

And Reynolds number is a dimensionless number which determines whether a flow is laminar or turbulent.  

Mathematically, we can write,

    Re = \frac{\rho .U.x}{\mu }

or 5 x 10^{5} =  \frac{\rho .U.x}{\mu } ( for a laminar flow )

Therefore, critical distance

x=\frac{5\times 10^{5}\times \mu }{\rho \times U}

So x is defined as the critical distance upto which the flow is laminar.

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Resistance to impact is an example of a(n)
Anika [276]

Answer:

Mechanical property

Explanation:

MECHANICAL PROPERTIES can be defined as the ability of a metal or material to remain undamaged after different type of forces has been applied or used on them because forces or loads are often applied to metal, material or physical properties which is why MECHANICAL PROPERTIES enables us to know the strength , toughness as well as the hardness of metal and the way this metal perform or react when different forces are applied on them.

Lastly any metal, material or physical properties that has the strength , hardness and resistance to withstand or remain unaffected despite the loads or forces use on them is an example of MECHANICAL PROPERTIES.

Therefore Resistance to impact is an example of a(n) MECHANICAL PROPERTIES.

8 0
2 years ago
Reduce the force F ij = + (2 5 ) kN to point A(2m,3m) that acts on point B( 3m,5m) - .
Alexxx [7]

Given :

Force, \vec{F}= (2\hat{i} + 5\hat{j})\ kN.

Force is acting at point A( 2 m, 3 m ) and B( 3 m, 5 m )

To Find :

The work done by force F .

Solution :

Displacement vector between point A and B is :

\vec{d} = (3-2)\hat{i} + (5-3)\hat{j}\\\\\vec{d} = \hat{i} + 2\hat{j}

Now, we know work done is given by :

W = \vec{F}.\vec{d}\\\\W= (2\hat{i} + 5\hat{j}).(\hat{i}+\hat{2j})\\\\W = (2\times 1) +( 5\times 2) \ kJ\\\\W = 12 \ kJ

W = 12000 J

Therefore, work done by force is 12000 J .

6 0
3 years ago
X cotx expansion using maclaurins theorem.
Lemur [1.5K]

It is to be noted that it is impossible to find the Maclaurin Expansion for F(x) = cotx.

<h3>What is Maclaurin Expansion?</h3>

The Maclaurin Expansion is a Taylor series that has been expanded around the reference point zero and has the formula f(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

<h3>What is the explanation for the above?</h3>

as indicated above, the Maclaurin infinite series expansion is given as:

F(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!

If F(0) = Cot 0

F(0) = ∝ = 1/0

This is not definitive,

Hence, it is impossible to find the Maclaurin infinite series expansion for F(x) = cotx.

Learn more about Maclaurin Expansion at;
brainly.com/question/7846182
#SPJ1

4 0
1 year ago
A home electrical system is joined to the electric company's system at the junction of the
aleksandrvk [35]

That would be B, I hope this helps!

5 0
3 years ago
Harmonic excitation of motion is represent as
Gennadij [26K]

Harmonic excitation refers to a sinusoidal external force of a certain frequency applied to a system. ... Resonance occurs when the external excitation has the same frequency as the natural frequency of the system. It leads to large displacements and can cause a system to exceed its elastic range and fail structurally.

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3 years ago
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