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il63 [147K]
3 years ago
7

Can you determine the critical distance along a flat surface?

Engineering
1 answer:
Keith_Richards [23]3 years ago
6 0

Explanation:

Consider a fluid of density, ρ moving with a velocity, U over a flat plate of length, L.

Let the Kinematic viscosity of the fluid be ν.

Let the flow over the fluid be laminar for a distance x from the leading edge.

Now this distance is called the critical distance.

Therefore, for a laminar flow, the critical distance can be defined as the distance from the leading edge of the plate where the Reynolds number is equal to 5 x 10^{5}

And Reynolds number is a dimensionless number which determines whether a flow is laminar or turbulent.  

Mathematically, we can write,

    Re = \frac{\rho .U.x}{\mu }

or 5 x 10^{5} =  \frac{\rho .U.x}{\mu } ( for a laminar flow )

Therefore, critical distance

x=\frac{5\times 10^{5}\times \mu }{\rho \times U}

So x is defined as the critical distance upto which the flow is laminar.

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As the complete question is not given the complete question is found online and is attached herewith.

By applying KCL at node 1

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V_{\Delta}=1K*i_y

Now applying KVL on loop 1 as indicated in the attached figure

1K*i_y+5K(i_y-i_z)+3K*i_x=0\\3i_x+6 i_y-5i_z=0

Similarly for loop 2

2V_{\Delta}+5K(i_z-i_y)=0\\2*1K*i_y+5K(i_z-i_y)=0\\2K*i_y+5K(i_z-i_y)=0\\3i_y-5i_z=0

So the system of equations become

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The values of i_x,i_y and i_z as 25 mA, -25 mA and 15 mA while that of V_Δ is -25 V

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