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3 years ago

Which of the fallowing elements would be least reactive a) iodine b) silicon c) silver d) argon

Chemistry

1 answer:

damaskus [11]3 years ago

5 0

Answer:

Noble Gases

Explanation:It's not on there but Noble gases is the least reactive element because it has 8 electrons and their outer energy is full.

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What frequency does television channel 7 broadcast at?

lana [24]

Answer:

Channel 7's frequency is 117.5 MHz

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3 years ago

Read 2 more answers

A piece of copper has a volume 130 L. What is the mass of the sample, in units of kilograms?

Reil [10]

Answer: The mass of the sample is 1264.800 kg.

Explanation:

Mass of the piece of copper = m

Volume of the copper price = $130 L=130,000 cm^3$

$1 L= 1,000 cm^3$

$Density=8.96 g/cm^3=\frac{Mass}{Volume}=\frac{Mass}{130,000 cm^3}$

$m=Density\times Volume=8.96 g/cm^3\times 130,000=1,264,800 g$

m = 1,264,800 g = 1,264.800 kg (1 kg = 1000 g)

The mass of the sample is 1264.800 kg.

3 0

3 years ago

A sheet of polyethylene 1.5-mm thick is being used as an oxygen barrier at a temperature of 600K. If the flux is 2.48 x 10-5 kg/

Eddi Din [679]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of high-pressure side is $C_1 = 0.722 \ kg/m^3$

Explanation:

From the question we are told that

The thickness of the polyethylene is $d = 1.5 \ mm = 0.0015 \ m$

The temperature is $T = 600 \ K$

The flux is $JA = 2.48 *10^{-5} \ kg/m^2\cdot s$

The concentration on the low-pressure side is $C_2 = 0.5 \ kg/m^3$

The initial diffusivity is $D_o = 6.2 *10^{-4} \ m^2 /s$

The activation energy for diffusion is $Q_d = 41 \ kJ /mol = 41*10^3 J /mol$

Generally the diffusivity of the oxygen at 600 K can be mathematically evaluated as

$D = D_o * e^{- \frac{Q_d}{R * T } }$

substituting values

$D = 6.2*10^{-4} * e^{- \frac{41 *10^3}{8.314 * 600 } }$

$D = 1.671 *10^{-7} \ m^2 /s$

Generally the flux is mathematically represented as

$JA = D * \frac{C_1 -C_2}{d}$

Where $C_1$ is the concentration of oxygen at the higher side

$C_1 = d * \frac{JA}{D} + C_2$

substituting values

$C_1 = 0.0015 * \frac{2.48*10^{-5}}{1.671*10^{-7}} + 0.5$

$C_1 = 0.722 \ kg/m^3$

6 0

3 years ago

Anabolic reactions may be characterized as

cluponka [151]

Anabolism is characterized as the assembly of large molecules from small molecules.

Anabolism is the set of chemical reactions of molecular synthesis of the organism considered. It is the opposite of catabolism, set of degradation reactions.

The reactions of the anabolism are reductions and are not spontaneous, they are endergonic reactions that is to say that they require a contribution in energy to take place. We can also talk about biosynthesis.

These reactions allow living organisms to synthesize essential metabolites from the basics provided by the diet and result in the building or renewal of tissues.

Examples: photosynthesis, protein biosynthesis.

6 0

2 years ago

Can anyone explain to me the octet rule in detail with examples my teacher didn't do the greatest job of making us understand.

iogann1982 [59]

In chemistry, the octet rule explains how atoms of different elements combine to form molecules. In a chemical formula, the octet rule strongly governs the number of atoms for each element in a molecule; for example, calcium fluoride is CaF2 because two fluorine atoms and one calcium satisfy the rule. Hope this helps

4 0

2 years ago