<h3>
Answer:</h3>
CdS
<h3>
Explanation:</h3>
<u>We are given;</u>
- % of cadmium is 78%
- % of sulfur is 22.0%
We are required to determine the empirical formula of cadmium sulfide
<h3>Step 1 : Determine the number of moles of Cadmium and sulfur </h3>
Assuming the mass of the cadmium sulfide is 100 g
Mass of cadmium is 78 g
Mass of sulfur is 22 g
But;
Moles = Mass ÷ Molar mass
Molar mass of Cadmium = 112.411 g/mol
Moles of Cadmium = 78 g ÷ 112.411 g/mol
= 0.694 moles
= 0.69 moles
Molar mass of sulfur is 32.065 g/mol
Moles of sulfur = 22 g ÷ 32.065 g/mol
= 0.686 moles
= 0.69 moles
<h3>Step 3: Determine the whole number mole ratio of Cadmium to sulfur</h3>
Cadmium : Sulfur
Cd : S
0.69 moles : 0.69 moles
0.69/0.69 : 0.69/0.69
1 : 1
Therefore, the empirical formula of greenockite is CdS
3.0x10-4..............................
Answer:
mammals are the animal who lay eggs
The tiny holes in a sponges outer layer that take in water are called ostia, I believe. Hope it helps