Answer:
R=100 Ohm, V=11.97 volts and I=0.12 amperes
R=10 Ohm, V=10.25 volts and I=1.20 amperes
R=2 Ohm, V=6.26 volts
Explanation:
The potential difference (voltage) of a battery with internal resistance is:
(1)
with
the electromotive force (the voltage the batteries say to has) , I the current and r the internal resistance. By Ohm's law the current that passes through the resistor is:
(2)
using (2) on (1):

solving for V:

(3)
R=100 Ohm

R=10 Ohm

R=2 Ohm

Because we have now the values of I on the circuit (is the same through all the components because is a series circuit)
We use back substitution on (1) to find the current:
R=100 Ohm

R=10 Ohm

Use the equation potential energy =m*g*h
m-mass,
g-gravitational acceleration,
h-height
Potential energy = 2*10*10
=200

This is the unit of the energy
I think it's called the Aphelion
Let Vpa be the velocity of plane with respect to air and Vp and Va be the velocities of plane and air respectively with respect to ground.
<span>Vpa = Vp - Va </span>
<span>Vp = Vpa + Va [all these quantities are vectors] </span>
<span>so by parallelogram law of vector addition </span>
<span>Vp = (Va^2 + Vpa^2 + 2*Va*Vpa*cos120)^(1/2) </span>
<span>Vp^2 = 33^2 + 140^2 - 33*140 </span>
<span>Vp^2 = 16096 </span>
<span>Vp = 126.763m/s </span>
<span>(2) tan b = (33*sin120)/(140+33/2) </span>
<span>b = 10.34 degrees North of East </span>
<span>(3) component of velocity of plane in east = Vp cos(10.34) = 126.763*1 = 126.7m/s </span>
<span>distance travelled by plane in east = 126.7 * 60*60=456120 m</span>
Explanation:
The magnetic field at the center of the wire is given by :

Here,
I is current flowing throgh the loop
r is the radius of loop
If the radius of the wire is doubled and the current is tripled, then new magnetic field is given by :

So, the new value of magnetic field gets 3/2th of the initial magnetic field.