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DIA [1.3K]
3 years ago
9

8 cups water a day is that measuring cups?

Physics
1 answer:
Gwar [14]3 years ago
4 0
No, it is 8 eight-once cups of water. 
Hope it helps! :)
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A non-ideal 12.2 V battery is connected across a resistor R. The internal resistance of the battery is 1.9Ohm. Calculate the pot
Brums [2.3K]

Answer:

R=100 Ohm, V=11.97 volts and I=0.12 amperes

R=10 Ohm, V=10.25 volts and I=1.20 amperes

R=2 Ohm, V=6.26 volts

Explanation:

The potential difference (voltage) of a battery with internal resistance is:

V=\xi-Ir (1)

with \xi the electromotive force (the voltage the batteries say to has) , I the current and r the internal resistance. By Ohm's law the current that passes through the resistor is:

I=\frac{V}{R} (2)

using (2) on (1):

V=\xi-\frac{V*r}{R}

solving for V:

V+\frac{V*r}{R}=\xi

V=\frac{\xi}{1+\frac{r}{R}} (3)

R=100 Ohm

V=\frac{12.2}{1+\frac{1.9}{100}}=11.97 V

R=10 Ohm

V=\frac{12.2}{1+\frac{1.9}{10}}=10.25 V

R=2 Ohm

V=\frac{12.2}{1+\frac{1.9}{2}}=6.26 V

Because we have now the values of I on the circuit (is the same through all the components because is a series circuit)

We use back substitution on (1) to find the current:

R=100 Ohm

I=\frac{V}{R}=\frac{11.97}{100}=0.12 A

R=10 Ohm

I=\frac{V}{R}=\frac{11.97}{10}=1.20 A

7 0
3 years ago
How much work is required to lift a 2 kg mass to a height of 10 meters?
scoray [572]
Use the equation potential energy =m*g*h
m-mass,
g-gravitational acceleration,
h-height
Potential energy = 2*10*10
=200
kg {m}^{2}   {s}^{ - 2}
This is the unit of the energy
6 0
3 years ago
The maximum distance between earth and sun occurs in july and is called the
Zina [86]
I think it's called the Aphelion
6 0
2 years ago
How far east will the plane travel in 1 hour?
MaRussiya [10]
Let Vpa be the velocity of plane with respect to air and Vp and Va be the velocities of plane and air respectively with respect to ground. 
<span>Vpa = Vp - Va </span>
<span>Vp = Vpa + Va [all these quantities are vectors] </span>
<span>so by parallelogram law of vector addition </span>
<span>Vp = (Va^2 + Vpa^2 + 2*Va*Vpa*cos120)^(1/2) </span>
<span>Vp^2 = 33^2 + 140^2 - 33*140 </span>
<span>Vp^2 = 16096 </span>
<span>Vp = 126.763m/s </span>
<span>(2) tan b = (33*sin120)/(140+33/2) </span>
<span>b = 10.34 degrees North of East </span>
<span>(3) component of velocity of plane in east = Vp cos(10.34) = 126.763*1 = 126.7m/s </span>
<span>distance travelled by plane in east = 126.7 * 60*60=456120 m</span>
3 0
3 years ago
Suppose I have a circular loop of wire with radius R. I run a current I through the loop and measure a magnetic field B at the c
just olya [345]

Explanation:

The magnetic field at the center of the wire is given by :

B=\dfrac{\mu_oI}{2r}

Here,

I is current flowing throgh the loop

r is the radius of loop

If the radius of the wire is doubled and the current is tripled, then new magnetic field is given by :

B'=\dfrac{\mu_oI'}{2r'}\\\\B'=\dfrac{\mu_o(3I)}{2(2r)}\\\\B'=\dfrac{3}{2}\times \dfrac{\mu_oI}{2r}\\\\B'=\dfrac{3}{2}\times B

So, the new value of magnetic field gets 3/2th of the initial magnetic field.

3 0
3 years ago
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