Answer:
False.
Explanation:
From Kepler's Third Law of plenetary motion, we know that:
<em>"The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit."</em>
Or, as expressed in mathematical terms:
, where <em>a</em> is the semi-major axis of the orbit (the distance from the center), and <em>T </em>is the orbital period of the satellite.
From this expression we can clearly see that if the orbit's semi-major axis is doubled, orbital period will be 
times longer to compensate the variation.
Answer:
32500N
Explanation:
Data obtained from the question include:
m (mass) = 2500 kg
a (acceleration) = 13 m/s2
F (force) =?
Force is the product of mass and acceleration. It is represented mathematically as:
Force = mass x acceleration
F = m x a
With the above formula, the force with which the car strikes the barrier can be obtained as follow:
F = m x a
F = 2500 x 13
F = 32500N
Therefore, the car will strike the barrier with a force of 32500N
Explanation:
A one-kilogram mass is still a one-kilogram(as mass is an intrinsic property of the object) but the downward force due to gravity, and therefore it's weight, is only one-sixth of what the object would have on the Earth. So man of mass 180 pounds weights only about 30 pounds-force when visiting the moon
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Becuse your weighting with chalk that has pigment
Responder:
6.704 m / s
Explicación:
Se dice que el trabajo se realiza cuando la fuerza aplicada a un objeto hace que el objeto se mueva. Primero necesitamos calcular la distancia recorrida por el perro usando la fórmula del trabajo realizado.
Trabajo realizado = Fuerza × distancia
Distancia = Trabajo realizado / Fuerza
Distancia = W / mg
S = 176/8 × 9,81
S = 176 / 78,48
S = 2,24 m
Dada la velocidad inicial u = 3.6km / h
Convertir a m / s
= 3.6km × 1000m / 1h × 3600
= 3600/3600
= 1 m / s
u = 1 m / s
Usando la ecuación de movimiento
v² = u² + 2gS para obtener la velocidad final v:
v² = 1² + 2 (9,81) (2,24)
v² = 1 + 43,9488
v² = 44,9488
v = √44,9488
v = 6,704 m / s
Por tanto, la rapidez final del perro es de 6,704 m / s
