A) a mouse, to an order of magnitude = 0.1 m ( a tenth of a meter ) That would be a big mouse but the alternatives are 1 meter or one hundredth of a meter... so go with 1/10th
<span>b) Easy = 1 meter </span>
<span>c) two choices 10m or 100 m . Go with 100 m </span>
<span>d) Stretch it out , trunk tip to tail tip - call it 10 m </span>
<span>e) Your choice 100 m or 1000 m..... These are estimates. So long as you are within one order of magnitude you can't really be given wrong. So I'd say 100m</span>
Answer:
the equilibrant is equal in magnitude but opposite in direction.
Explanation:
In vector algebra, a resultant vector is a single vector that have the same effect as the effect of the net or algebraic sum of two or more vectors.
A resultant vector arises from finding the adding multiple vectors together.
When a group of vectors is replaced by a resultant vector, in order to keep the system of vectors at equilibrium, there is another vector which has the same magnitude as the resultant vector but acting in opposite direction to the resultant vector. This vector is called the equilibrant.
False, fission is when an atom splits into two parts.
A) The stone moves along the vertical direction by unifom accelerated motion, with acceleration equal to g (gravitational acceleration), starting from initial position h above the ground and with initial velocity equal to zero. So, its vertical position follows the law:
b) The time the stone takes to reach the ground is the time t at which its vertical position y(t) becomes zero:
and if we solve it, we find
c) Since it is a uniform accelerated motion, the velocity of the stone at time t is given by
where the initial velocity is zero:
. The stone hits the ground at t=9.6 s, so its velocity at that time is
where the negative sign means it is directed downward.
d) In this case, since the initial velocity is not zero, the position at time t is given by
where
is the initial velocity.
The time the stone takes to reach the ground is the time t such that y(t)=0, so we have:
and by solving this equation, we find