Answer:
4.5 s, 324 ft
Explanation:
The object is projected upward with an initial velocity of
The equation that describes its height at time t is
(1)
where t, the time, is measured in seconds.
In order to find the time it takes for the object to reach the maximum height, we must find an expression for its velocity at time t, which can be found by calculating the derivative of the position, s(t):
(2)
At the maximum heigth, the vertical velocity is zero:
v(t) = 0
Substituting into the equation above, we find the corresponding time at which the object reaches the maximum height:
And by substituting this value into eq.(1), we also find the maximum height:
Answer:
The velocity of the ship relative to the earth V = 9.05 
Explanation:
The local ocean current is = 1.52 m/s
Direction 
= 40°
Velocity component in X - direction 
= 1.52 
°
= 1.164
Velocity component in Y - direction 
= 8 + 1.52 
°
= 8.97
The velocity of the ship relative to the earth
Put the values of and we get,
⇒ 
⇒ V = 9.05
This is the velocity of the ship relative to the earth.
Acceleration is the rate at which an object changes its velocity. It defines how much the velocity is changing. The acceleration can be negative and positive. Negative acceleration is when the object slows down, while positive while the object goes faster.
<span>A ball moving at a constant speed around a circular track produces acceleration. </span>
The resultant vector can be determined by the component vectors. The component vectors are vector lying along the x and y-axes. The equation for the resultant vector, v is:
v = √(vx² + vy²)
v = √[(9.80)² + (-6.40)²]
v = √137 or 11.7 units
