Acceleration = (change in speed) / (time for the change) = 9/3 = <em>3 m/s²</em> .
His mass makes no difference.
Answer:
<h2>5.53 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula

m is the mass
v is the velocity
From the question we have

We have the final answer as
<h3>5.53 J</h3>
Hope this helps you
Answer:
a. 25m
b. 25m
c. 35m
Explanation:
Given the distances walked as 15m east and 20m north:
Using Pythagoras Theorem, we calculate displacement as:

Hence, the resultant displacement is 25m
b. The distance from her start point is obtained by drawing a straight line from her final point to her initial point.
Given the distances walked as 15m east and 20m north:
Using Pythagoras Theorem, we calculate displacement as:

Hence, she is 25m away from her starting point.
c. The distance traveled is calculated by summing the total distance walked:

Hence, the total distance traveled is 35m
Answer:
Idk I think we all ask the question also this question is for sure prob getting deleted just saying now not by me
Explanation:
Here the weight is hung from the thread inside the ceiling of train
now the FBD of train is analysed
We can say


now by ratio of two equations we have

this shows that train must be in accelerating condition due to which the thread is making an angle with the vertical
now we will have
2 The train is not an inertial frame of reference.
Since train is accelerating so it must be non inertial frame
5 The train may be moving at a constant speed in a circle.
Since its moving in circle so it is in accelerating condition
8 The train must be accelerating.