The acceleration is -9.8m/s^2. The initial velocity is -8m/s. The initial position is 30m. This describes a position function of
-(9.8/2)t^2-8t+30=0
Solve the quadratic equation for t to get t=1.789s
Answer:
the answer is 3600 kilometers
I'm pretty sure the answer is B: <span>establish public doubt
Hope this helps!</span>
Answer:
The bullet will have been dropped vertically h= 0.54 meters by the time it hits the target.
Explanation:
d= 100m
V= 300 m/s
g= 9.8 m/s²
d= V*t
t= d/V
t= 0.33 s
h= g*t²/2
h=0.54 m
