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astra-53 [7]
3 years ago
10

What is a substance

Physics
1 answer:
Ulleksa [173]3 years ago
4 0

Well, if i am correct. a substance is:

a particular kind of matter with uniform properties

or...

the real physical matter of which a person or thing consists and which has a tangible, solid presence.

choose which ever you like better:)

You might be interested in
The one star that does not appear as a small point of light is called
seraphim [82]

The sun. lol. It is closer to Earth, therefore bigger to us, and not just a small point of light.

5 0
3 years ago
This is the process of water changing from a gas to a liquid. You will see clouds forming when this happens.
Goryan [66]
Its called condensation. condensation is <span>water that collects as droplets on a cold surface when humid air is in contact with it. aka. clouds</span>
4 0
3 years ago
5) Find the initial velocity for a 700 kg car that
Serhud [2]

Answer:

Δv = 12 m/s, but we are not given the direction, so there are really an infinite number of potential solutions.

Maximum initial speed is 40.6 m/s

Minimum initial speed is 16.6 m/s

Explanation:

Assume this is a NET impulse so we can ignore friction.

An impulse results in a change of momentum

The impulse applied was

p = Ft = 1400(6.0) = 8400 N•s

p = mΔv

Δv = 8400 / 700 = 12 m/s

If the impulse was applied in the direction the car was already moving, the initial velocity was

vi = 28.6 - 12 = 16.6 m/s

if the impulse was applied in the direction opposite of the original velocity, the initial velocity was

vi = 28.6 + 12 = 40.6 m/s

Other angles of Net force would result in various initial velocities.

5 0
3 years ago
Determine the kinetic energy of a 1000-kg roller coaster car that is moving with a speed of 20.0 m/s.
ankoles [38]

Answer:

The correct answer is - 200000 J

Explanation:

We use the formula of kinetic energy:

The formula to calculate kinetic energy is,

Here,

Ec =1/2 x  m x v^2

The mass of the roller coaster is,  m  =  1000  k g

The speed of the roller coaster is, v = 20.0 m/s

 Therefore,

Ec=1/2 x 1000kg x (20m/s)^2 = 200.000Joule

200,000J

7 0
3 years ago
how do you define two angles which will result in a range of zero for a projectile launched at an angle to the horizontal
Mrrafil [7]
Oh what a sneaky problem ! 

The "range" of a projectile is how far out away from the gun it goes
before it falls to the ground.

The question is asking you:  "What angle should you aim the gun
above the horizon so that the bullet doesn't go <em>any</em> distance away
from the gun, and it hits the ground exactly where the gun is "
And there are two different answers.  Really sneaky !

Can you think of how you could fire the gun so that the bullet would
hit the ground right under the gun ?  How about pointing the gun at
the ground ... aiming 90 degrees <em>below</em> the horizon ?  That would
certainly do it.                Is there another way to do it  ?

How about aiming the gun straight up in the air ... 90 degrees <em>above</em>
the horizon ?  Then it goes up, up, up, runs out of steam, stops rising,
starts falling, comes down, down, down, and hits the ground right where
the gun was.

As long as there's no air and no wind, the two angles are +90 degrees
and -90 degrees above the horizon. 

' +90 above ' means straight up.  ' -90 above ' means straight down.

8 0
3 years ago
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