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astra-53 [7]
3 years ago
10

What is a substance

Physics
1 answer:
Ulleksa [173]3 years ago
4 0

Well, if i am correct. a substance is:

a particular kind of matter with uniform properties

or...

the real physical matter of which a person or thing consists and which has a tangible, solid presence.

choose which ever you like better:)

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Where is the fish in reality
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In reality, the fish are in the ocean.
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An Elephant is pulled by a group of clowns across a circus. The elephant has a mass of 1000kg and the clowns are pulling with a
ycow [4]

Answer:

Acceleration = 0.2m/s²

Explanation:

Given the following data;

Mass = 1000kg

Force = 200N

To find acceleration;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

F = ma

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

Acceleration (a) = \frac{F}{m}

Substituting into the equation;

Acceleration (a) = \frac{200}{1000}

Acceleration = 0.2m/s²

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Why do you think the sickle cell allele is still common in tropical regions?
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8 0
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You have two pieces of wire that allow electrons to pass through them when they are connected to each other. If you insert a pie
hoa [83]
Out of the following choices given, if you insert a piece of rubber between the wires, the electrons do not flow. The rubber material is an insulator. The correct answer is D. 
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use the general formulas for gravitational force and centripetal force to derive the relationship between speed and orbital radi
MrRissso [65]

Answer:

v = \sqrt{\frac{GM}{r}}

Explanation:

The universal law of gravitation is defined as:

F = G\frac{Mm}{r^{2}}  (1)                

Where G is the gravitational constant, M and m are the masses of the two objects and r is the distance between them.

The centripetal force can be found by means of Newton's second law:

F = ma  (2)

Since it is a circular motion, the acceleration can be defined as:

a = \frac{v^{2}}{r}  (3)

Where v is the velocity and r is the orbital radius.

Replacing equation (3) in equation (2) it is gotten:

F = m\frac{v^{2}}{r}  (4)

Hence,

m\frac{v^{2}}{r} = G\frac{Mm}{r^{2}}

Then, v can be isolated:

mv^{2} = G\frac{Mmr}{r^{2}}

mv^{2} = G\frac{Mm}{r}

v^{2} = G\frac{Mm}{mr}

v^{2} = \frac{GM}{r}

v = \sqrt{\frac{GM}{r}}

So the relationship between speed and orbital radius is given by the expression v = \sqrt{\frac{GM}{r}}

8 0
3 years ago
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