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3 years ago

What is a substance

Physics

1 answer:

Ulleksa [173]3 years ago

4 0

Well, if i am correct. a substance is:

a particular kind of matter with uniform properties

or...

the real physical matter of which a person or thing consists and which has a tangible, solid presence.

choose which ever you like better:)

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A 4.5-kg, three legged stool supports a 89-kg person. If each leg of the stool has a cross-sectional diameter of 2.8 cm and the

kkurt [141]

Answer:

4.96 × 10⁵ Pa

Explanation:

F = mg

$F = (m_{person}+m_{stool})g\\\\F = (4.5 + 89)*9.8\\\\F = 916.3 N$

This force is evenly distributed on the three leg

radius, r = d/2

= 2.8 / 2

= 1.4 cm = 0.014 m

total cross sectional area of the three legs, A = 3*pi*r^2

$= 3\times\pi \times0.014^2\\\\= 1.847\times10^-^3m^2$

Pressure due to weight,

P = Weight/A

$P = / 1.847 × 10⁻³\\P = \frac{ 916.3N}{1.847\times10^-^3} \\\\P= 496032.9Pa$

P = 4.96 × 10⁵ Pa

8 0

3 years ago

Please somebody answer I desperately need help!

padilas [110]

Preserved fossil<span> (like a fossil in amber, ice or tar.</span>

8 0

3 years ago

Read 2 more answers

A bus starts to move from rest. If its velocity becomes 90 km/hr after 8 seconds, calculate its acceleration.

a_sh-v [17]

Answer:

The acceleration is 11.25 km/hr

Explanation:

Divide the velocity over time to find the acceleration. The bus is accelerating 11.25 km/hr per second in the range of 8 seconds

7 0

3 years ago

A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector 1,=1.91 m and 1,=−2.73 m in

Elena-2011 [213]

Answer:

Components: 0.0057, -0.0068. Magnitude: 0.0089 m/s

Explanation:

The displacement in the x-direction is:

$d_x = 3.65-1.91=1.74 m$

While the displacement in the y-direction is:

$d_y = -4.79 -(-2.73)=-2.06 m$

The time taken is t = 304 s.

So the components of the average velocity are:

$v_x = \frac{d_x}{t}=\frac{1.74}{304}=0.0057 m/s$

$v_y = \frac{d_y}{t}=\frac{-2.06}{304}=-0.0068 m/s$

And the magnitude of the average velocity is

$v=\sqrt{v_x^2+v_y^2}=\sqrt{(0.0057)^2+(-0.0068)^2}=0.0089 m/s$

8 0

3 years ago

A flywheel of J = 50 kg-m2 initially standing still is subjected to a constant torque. If the angular velocity reaches 20 Hz in

Karolina [17]

Answer:

$\tau = 1256.5\ N.m$

Explanation:

given,

J = 50 kg-m²

frequency, f = 20 Hz

time ,t = 5 s

we know,

angular velocity = 2 π f

ω = 2 π x 20

ω = 125.66 rad/s

now, angular acceleration calculation

$\alpha = \dfrac{\omega_f-\omega_i}{t}$

$\alpha = \dfrac{125.66-0}{5}$

α = 25.13 rad/s²

Torque given to the flywheel.

$\tau = I \alpha$

$\tau = 50\times 25.13$

$\tau = 1256.5\ N.m$

Torque of the given flywheel is equal to $\tau = 1256.5\ N.m$

7 0

3 years ago