1) 29.8 C
At the beginning, the metal is at higher temperature (70.4 C) while the water is at lower temperature (23.6 C). When they are put in contact, the metal transfers heat to the water, until they reach thermal equilibrium: at thermal equilibrium the two objects (the metal and the water have same temperature). Therefore, since the temperature of the water at thermal equilibrium is 29.8 C, the final temperature of the metal must be the same (29.8 C).
2) 6.2 C
The temperature change of the water is given by the difference between its final temperature and its initial temperature:
where
Substituting into the formula,
And the positive sign means that the temperature of the water has increased.
3) -40.6 C
The temperature change of the metal is given by the difference between its final temperature and its initial temperature:
where
Substituting into the formula,
And the negative sign means the temperature of the metal has decreased.
Answer:
a) 22.471 x 10^-11 N
b) -22.471 x 10^-11 N
Explanation:
given the charge on an electron = 1.6 x 10^-19 C
nucleus contain 79 protons
hence, charge on nucleus =79 x 1.6 x 10^-19 C
distance r = 9 x 10^-9 m
a) therefore, force exerted by the gold nucleus on the electron = Kqe/r^2
= 9 x 10^9 x 79 x 1.6 x 10^-19 x 1.6 x 10^-19 / ( 9 x 10^-9 m)^2
= 22.471 x 10^-11 N
b) force exerted by the electron on the gold nucleus ; = -Force exerted by gold on electron ( From newton third law of motion)
= - 22.471 x 10^-11 N
We use the voltage division problem between the load resistance, amplifier output resistance as
.
Here, is the output voltage, is the amplifier voltage, is the load resistance and is the amplifier output resistance.
Therefore,
.
Thus, the amplifier output resistance is .
Answer:
(a)0.625s (b)1.569s
Explanation:
a.The ball reaches its maximum height when its speed = 0, or changing from positive to negative. To find out the time t for this we need to get the velocity function by taking the first derivative of the height function:
So when v(t) = 0
b. The ball land back on the ground when s(t) = 0:
15.00 g / 5.0 cm³ = (15.00 ÷ 5.0) g / cm³ = 3.0 g / cm³ .
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