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JulijaS [17]
3 years ago
6

Consider an ideal gas at 27.0 degrees Celsius and 1.00 atmosphere pressure. Imagine the molecules to be uniformly spaced, with e

ach molecule at the center of a small cube. What is the length of an edge of each small cube if adjacent cubes touch but don't overlap?
Physics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

The length of an edge of each small cube  is 3.43 nm.

Explanation:

Given that,

Temperature of ideal gas =27.0°C

Pressure = 1.00 atm

We need to calculate the length of an edge of each small cube

Using gas equation

PV=nRT

PV=NkT

V=\dfrac{NkT}{P}

For, N = 1

Where,

N = number of molecule

k = Boltzmann constant

T = temperature

P= pressure

Put the value into the formula

V=\dfrac{1\times1.38\times10^{-23}\times(27+273)}{1.03\times10^{5}}

V=4.019\times10^{-26}\ m^3

Now, for the cube

V=L^3

L=V^{\frac{1}{3}}

L=(4.019\times10^{-26})^{\frac{1}{3}}

L=3.43\times10^{-9}\ m

L=3.43 nm

Hence, The length of an edge of each small cube  is 3.43 nm.

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At its peak, a tornado is 53.0 m in diameter and carries 465-km/h winds. What is its angular velocity in revolutions per second?
expeople1 [14]

Answer:

0.7757 rev/s

Explanation:

d = Diameter of the tornado = 53 m

r = Radius of the tornado = 53/2 = 26.5 m

v = Velocity of wind = 465 km/h

Converting velocity to m/s

465=465\times \frac{1000}{3600}=\frac{775}{6}

Angular velocity

\omega=\frac{v}{r}\\\Rightarrow \omega=\frac{\frac{775}{6}}{26.5}\\\Rightarrow \omega=4.87\ rad/s

\omega=4.87\frac{1}{2\pi}=0.7757\ rev/s

∴ Angular velocity is 0.7757 rev/s

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3 years ago
Give an example of Newton's 1st law​
Vesna [10]

Answer:

A ball moving until gravity pulls it back down to the ground

Explanation:

5 0
3 years ago
Estimate how fast your hair grows, in units of m/s, assuming it takes 30 days for your hair to grow 1 inch. note that 1 inch =2.
dedylja [7]

Answer:

1) 9.8×10⁻⁹ m/s

2) 50970.3238656 L

Explanation:

1) In 30 days hair grows 1 inch

1 inch = 2.54 cm

1 cm = 0.01 m

2.54 cm = 2.54 × 0.01 m

⇒2.54 cm = 0.0254 m

30 days = 30×24×60×60 = 2592000 seconds

Speed = Distance / Time

\text{Speed}=\frac{0.0254}{2592000}=9.8\times 10^{-9}\ m/s

Speed at which hair grows is 9.8×10⁻⁹ m/s

2) 1 ft = 0.3048 m

0.3048 m = 30.48 cm

1 ft = 30.48 cm

15 ft = 15×30.48 = 457.2 cm

8 ft = 8×30.48 = 243.84 cm

Volume of water in pool = Length × Width × Depth

⇒Volume of water in pool = 457.2×457.2×243.84

⇒Volume of water in pool = 50970323.8656 cm³

or

Volume of water in pool = 15×15×8 = 1800 ft³

1 ft³ = 30.48³ cm³

1800 ft³ = 30.48³ × 1800 = 50970323.8656 cm³

Converting to liters

1 L = 1000 cm³

0.001 L = 1 cm³

50970323.8656 cm³ = 50970323.8656×0.001 = 50970.3238656 L

Volume of water in pool is 50970.3238656 L

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Answer:Argon

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