Answer:
21.28 grams solute can be added if the temperature is increased to 30.0°C.
Explanation:
Solubility of solute at 20°C = 32.2 g/100 grams of water
Solute soluble in 1 gram of water =
Mass of solute in soluble in 56.0 grams of water:
Solubility of solute at 30°C = 70.2g/100 grams of water
Solute soluble in 1 gram of water =
Mass of solute in soluble in 56.0 grams of water:
If the temperature of saturated solution of this solute using 56.0 g of water at 20.0 °C raised to 30.0°C
Mass of solute in soluble in 56.0 grams of water 20.0°C = 18.032 g
Mass of solute in soluble in 56.0 grams of water at 30.0°C = 39.312 g
Mass of of solute added If the temperature of the saturated solution increased to 30.0°C:
39.312 g - 18.032 g = 21.28 g
21.28 grams solute can be added if the temperature is increased to 30.0°C.
Answer:
12
Explanation:
because that plot and the iron
To melt a solid, energy must be input into the solid to give the molecules high energy to disrupt the lattice bonds and change phase. To return the liquid to solid, the same amount of energy used in melting is required to be removed from the liquid, ideally. This is assuming there is no loss of energy in the process.
Answer:
This is confusing
but if you still need help, you can search it online
Explanation:
Copper= 79.853%
Sulfide= 20.147%
Hope this helps.