We want to use this primary leaving group on this primary starting material because it will give us a greater yield and say, if we were to use a secondary reagent in place of this primary.
Now we've moved on from our fundamentals. So we have our starting material and we have That's our beautiful sec futile ether. So now that we've written out are starting material, we can take a thing about where exactly some reactivity may happen. So, for example, could start out with an alcohol that looks as the following. This is a secondary alcohol you can see. So now we need to take a look at some of alcohol.
So now we need to think about our alcohol. Hey, light again. Well, we'll have a hey light. That's a very good leaving group. So we need alcohol. So for example, so now we have a primary structure here, So this will undergo and s and two reaction due to the lacking of hysteric hindrance. Formal negative charge attacks that electrical it carbon bro.
Learn more about Alcohol here-
brainly.com/question/14229343
#SPJ4
Answer:
2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²
Explanation:
A redox reaction occurs between a compound that loses electrons and others that gain an electron. The first is being oxidized, and the other is being reduced.
In this situation, in the compound Fe₂O₃, the iron, has an oxidation number equal to +3, so it's Fe⁺³, and it will gain 1 electron to become Fe⁺². Because it was first dissolved in HCl, we must use the ion at the equation. The other compound Sn₂ will be oxidized to Sn⁺², so it will need to lose 2 electrons.
So, it will be necessary 2 Fe⁺³ for this reaction happen:
2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²
Lithium is a good reducing agent because it is electropositive [it rapidly gains electrons]
fluorine is good oxidizing agent electronegative [it loses electrons fastly]
