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ASHA 777 [7]
3 years ago
12

Calculate the number of atoms in 52g of He.​

Chemistry
1 answer:
MissTica3 years ago
5 0

Answer:

78.3 × 10²³ atoms of helium are present in 52 g.

Explanation:

Given data:

Mass of He = 52 g

Number of atoms = ?

Solution:

First of all we will calculate the number of moles of He

Number of moles = mass /molar mass

Number of moles = 52 g/ 4 g/mol

Number of moles = 13 mol

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole = 6.022 × 10²³ atoms of helium

13 mol  × 6.022 × 10²³ atoms of helium  / 1 mole

78.3 × 10²³ atoms of helium

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3 years ago
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How much energy does it take to boil 100 mL of water?
yawa3891 [41]

Answer:

the answer is D. Because the 1 atm pressure of water is 40.65 or 40.7.

8 0
2 years ago
A solution of malonic acid, H2C3H2O4 , was standardized by titration with 0.1000 M NaOH solution. If 21.17 mL of the NaOH soluti
MrRa [10]

Answer: The molarity of the malonic acid solution is 0.08335 M

Explanation:

H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_3H_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL

Putting values in above equation, we get:

2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M

Thus the molarity of the malonic acid solution is 0.08335 M

5 0
3 years ago
For the reaction, identify the Lewis acid and the Lewis base.<br> AlF3 + CH3F → CH3+ + [AlF4]-
Ivanshal [37]
Answer:
            AlF₃ is Lewis Acid

            CH₃F is Lewis Base

Explanation:
                     According to Lewis concept ,"those compounds which donate pair of electrons are called as Lewis Base and those accepting pair of electrons are called as Lewis Acid.

In Given Reaction,
<span>                               AlF</span>₃<span> + CH</span>₃<span>F → CH</span>₃⁺<span> + [AlF</span>₄<span>]</span>⁻

AlF₃ is acting as acid because the octet of Al is not complete, hence it has tendency to accept electrons.

CH₃F is acting as a base because the F atom containing three lone pair of electrons can donate it to Al metal resulting in the formation of electrophile i.e. CH₃⁺.
5 0
3 years ago
ASAP
MissTica

Answer:4 M

Explanation:google

7 0
3 years ago
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