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ASHA 777 [7]
3 years ago
12

Calculate the number of atoms in 52g of He.​

Chemistry
1 answer:
MissTica3 years ago
5 0

Answer:

78.3 × 10²³ atoms of helium are present in 52 g.

Explanation:

Given data:

Mass of He = 52 g

Number of atoms = ?

Solution:

First of all we will calculate the number of moles of He

Number of moles = mass /molar mass

Number of moles = 52 g/ 4 g/mol

Number of moles = 13 mol

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole = 6.022 × 10²³ atoms of helium

13 mol  × 6.022 × 10²³ atoms of helium  / 1 mole

78.3 × 10²³ atoms of helium

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Answer:

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Explanation:

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6 0
2 years ago
Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
galina1969 [7]

Answer:

\%\, yield\, \, SO_3=82.29

Explanation:

First write the balance eqation of chemical reaction:

2S(s) +3O_2(g) \rightarrow 2SO_3(g)

Remember writing any chemical reaction from its  elemetal form then write the elements in their natural form i.e. how that element exists in the nature here sulphur exists in solid monoatomic form in the nature and oxygen in gaseous diatomic form.

mass of oxygen given=5gram

mole of oxygen=5/32mol=0.16mol

mass of sulpher given=6gram

mole of sulpher=6/32mol=0.19mol

from the above balanced equaion;

2 mole of sulphur reacts with 3 mole Oxygen completely

1 mole of sulphur reacts with 1.5 mole Oxygen completely

0.19 mole of sulphur reacts with 1.5\times 0.19 i.e. 0.285 mole Oxygen completely.

but we have 0.16 mole so oxygen will be the limiting reagent and sulpher will be the excess reagent

so product will depend on the limiting reagent

from the balance equation

3 mole of sulpher gives 2 mole SO_3

1 mole of sulpher will give 2/3 mole SO_3

0.16 of sulpher will give 0.12 mole SO_3

mass of SO_3=9.6gram this is theoreical production of SO_3

and

actual production of SO_3 =7.9gram

\%\, yield   \,\, SO_3=\frac{Actual \,yield}{theoretical\, yield}\times 100

\%\, yield\, \, SO_3=\frac{7.9}{9.6} \times 100=82.29

\%\, yield\, \, SO_3=82.29

3 0
2 years ago
How many more grams should be added​
Minchanka [31]

Answer:

50?

I think but not 100% sure if not lmk

4 0
3 years ago
CAN SOMEONE PLEASE HELP ME ASAP?!!!!
krok68 [10]
A and d is physical, b and c is chemical
4 0
3 years ago
How many electrons must calcium lose to satisfy the octet rule?
earnstyle [38]

Answer:

Lose 2 electrons

Explanation:

8 0
3 years ago
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