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natka813 [3]
3 years ago
12

Ferns spread spores instead of seeds, and some ferns eject the spores at surprisingly high speeds. One species accelerates 1.4 μ

g spores to a 4.5 m/s ejection speed in a time of 1.0 ms. What impulse is provided to the spores? What is the average force on a spore?
Physics
1 answer:
marta [7]3 years ago
5 0

Answer:

Impulse is 6.3*10^{-9}\:N \cdot s

The average force is 6.3*10^{-6} N

Explanation:

When a mass m undergoes a change in velocity \Delta v, its impulse I is

I =m\Delta v

and if a force F is acting for time t, then the impulse I is given by

I=F*t

Now the mass of the spores in kg is

m=1.4*10^{-6}g*\frac{10^{-3}kg}{g}=1.4*10^{-9}kg

we calculate the impulse from the first formula:

I =m\Delta v =(1.4*10^{-9}kg)(4.5\frac{m}{s} )=6.3*10^{-9}N\cdot s

\boxed{I=6.3*10^{-9}\:N \cdot s}

Now that we have impulse, we calculate the average force on the spore from the second formula:

F=\frac{I}{t} =\frac{6.3*10^{-9}}{1*10^{-3}s}=6.3*10^{-6} N

\boxed{F=6.3*10^{-6} N}

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