Answer:
Yes
Explanation: Electric and magnetic field are known to be inter-related, this implies that for any current carrying conductor there is a resulting magnetic field around the wire ( for example a current carrying conductor deflects a compass) and a magnetic field has been known to produce some amount current based on the<em> </em>principle of electromagnetic induction by Micheal Faraday.
The strength of magnetic field generated by a current carrying conductor is given by Bio-Savart law (purely mathematical) which is
B =
B= strength of magnetic field
I =current on conductor
r = distance on any point of the conductor relative to it center
If a current carrying could generate this magnitude of magnetic field, thus this magnetic field has the ability to interact (exert a force on any magnetic material) with any other magnetic material including a magnet.
Yes, a current carrying conductor can exert a force on a magnetic field
Solid is a state
of matter having no space in a volume, made entirely of compact material.
Solute is a
dissolved substance is a dissolved substance in a solution.
Solution is the
one that dissolves the solute.
Solvent is the
one that dissolves either a solution or solute.
Based on the
definitions, the answer is letter B. solute.
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Answer:
v₂=- 34 .85 m/s
v₁=0.14 m/s
Explanation:
Given that
m₁=70 kg ,u₁=0 m/s
m₂=0.15 kg ,u₂=35 m/s
Given that collision is elastic .We know that for elastic collision
Lets take their final speed is v₁ and v₂
From momentum conservation
m₁u₁+m₂u₂=m₁v₁+m₂v₂
70 x 0+ 0.15 x 35 = 70 x v₁ + 0.15 x v₂
70 x v₁ + 0.15 x v₂=5.25 --------1
v₂-v₁=u₁-u₂ ( e= 1)
v₂-v₁ = -35 --------2
By solving above equations
v₂=- 34 .85 m/s
v₁=0.14 m/s
The answer is C the temp of water in both beakers will decrease since the metal is flowing heat into the water. Therefore we can say the metal losses heat and the water gains the heat lost by the metal minus any heat loss to surroundings! Hope this explanation helps you understand the concept! Please rate if I helped you! Thank you so much!
Answer:
the field at the center of solenoid 2 is 12 times the field at the center of solenoid 1.
Explanation:
Recall that the field inside a solenoid of length L, N turns, and a circulating current I, is given by the formula:
Then, if we assign the subindex "1" to the quantities that define the magnetic field (
) inside solenoid 1, we have:
notice that there is no dependence on the diameter of the solenoid for this formula.
Now, if we write a similar formula for solenoid 2, given that it has :
1) half the length of solenoid 1 . Then 
2) twice as many turns as solenoid 1. Then 
3) three times the current of solenoid 1. Then 
we obtain:
