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dusya [7]
3 years ago
5

Before factories made large-scale production possible, what type of workers produced goods like shoes or cloth?

Engineering
1 answer:
DanielleElmas [232]3 years ago
4 0

Answer:craftsman

Explanation:

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You gently place several steel needles on the free surface of the water in a large tank. The needles come in two lengths: some a
Stolb23 [73]

Answer:

attached below

Explanation:

4 0
3 years ago
True or false? the arc welding power voltage used for GMAW and FCAW produces a constant voltage​
7nadin3 [17]

Answer:

False

Explanation:

3 0
3 years ago
A cylinder is to be cast out of aluminum. The diameter of the disk is 500 mm and its thickness is 20 mm. The mold constant 2.0 s
Nezavi [6.7K]

Answer:

a) the minimum time (minutes) for the aluminium casting to solidify is 2.86 min

b) the minimum time (minutes) for the grey iron casting to solidify is 2.13 min. Therefore solidification of grey iron cast will take less time (2.13 min) compared to the solidification of the aluminium cast (2.86 min)

Explanation:

Given that; diameter of Disk = 500 mm, thickness t = 20, mold constant Cm = 2.0 sec/mm²

first we find the volume and Area;

Volume V = πD²t / 4

Volume V = π × (500)² × 20 / 4 = 3,926,991 mm³

Area A = 2πD²/ 4 + πDt

Area A = {[π × (500)²] / 2} +{ π × (500) × (20)}

Area A = 392,699.08 + 31,415.93

Area A = 424,115 mm²

a)

Chvorinov’s rule

T(aluminium) = Cm (V/A) ²

T(aluminium) =  2.0 × (3,926,991 / 424,115) ²

T(aluminium) = 171.5 s = 2.86 min

∴ the minimum time (minutes) for the casting to solidify is 2.86 min

b)

For cast iron

Cm (mold constant = 1.488 sec/mm²)

Chvorinov’s rule

T(iron) = Cm (V/A) ²

T(iron) = 1.488 × (3,926,991 / 424,115) ²

T(iron) = 127.5720s = 2.13 min

Therefore solidification of grey iron cast will take less time (2.13 min) compared to the solidification of the aluminium cast (2.86 min)

6 0
4 years ago
When a starter motor begins to turn it produces a high…. *
Georgia [21]

Answer:

The motor produces a high Torque when it begins to start.

8 0
3 years ago
Air enters a compressor operating at steady state at 1 atm with a specific enthalpy of
Savatey [412]

Answer:

option C

option A

Explanation:

Enthalpy gained by air= 1023-290

                                       = 733 kJ/kg

Rate of energy gain= mass flow rate × Enthalpy gained by air

                               = 0.1 × 733

                            = 73.3 kJ/s

rate of heat transfer between compressor and air= 77kW

Heat loss by air to surroundings= 77-73.3

                                                     =3.7kW

Enthalpy lost by steam in turbine= 1407.6-1236.4

                                                     = 171.2 Btu/lb

Rate of energy transfer to turbine= Enthalpy lost by steam× mass flow rate

                                                    = 171.2×5

                                                     = 856 Btu/s

Net rate of energy transfer to turbine=rate of  Energy transfer to turbine- rate of heat transfer to turbine

                          = 856-40

                         = 816 Btu/s

8 0
4 years ago
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