An object is placed in front of a lens at 10cm from its optic centre.The image is seen on the same side of lens at 60cm distance
1 answer:
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Answer:
Explanation:
Given two objects are dropped simultaneously
Object A is 10 m higher than object B therefore
Distance covered by object A is given by
is given by
where y=displacement
u=initial velocity
a=acceleration
t=time
for object B
Subtract 1 and 2 we get
i.e. they will travel equal distance in equal time and distance between them remain 10 m until object B hits the ground
Answer:
Both will reach to same height
Explanation:
Here we can see that friction is to be ignored
so we can say that work done by all the non conservative forces is change in mechanical energy
Since all non conservative forces here is zero
so mechanical energy is conserved here
so here we can say that sum of initial kinetic energy and potential energy = sum of final kinetic energy and potential energy
So we will have
now maximum height is given as
so here we can say that greatest height will be independent of the mass so they both will reach at same height