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BigorU [14]
4 years ago
9

imagine that a new planet is discovered with two moons of equal mass, moon A and moon B. The mass of the new planet is greater t

han the combined mass of its moons. Moon A is farther away from the new planet than moon B. What is the planets gravitational pull on moon A compared to the gravitational pull on moon B
Physics
2 answers:
kicyunya [14]4 years ago
4 0
When two objects are farther apart, the gravitational attraction
between them is weaker.

This is a big part of the reason why we are more strongly attracted
to the Earth than we are to Jupiter or to the Sun.


sdas [7]4 years ago
3 0
The gravitational pull on moon A will be lower since it is further away from the new planet.
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A cylindrical insulated wire of diameter 5.0 mm is tightly wound 200 times around a cylindrical core to form a solenoid with adj
laiz [17]

Answer:

0.0016 T

Explanation:

Parameters given:

Diameter of wire = 5 mm = 0.005 m

Radius of wire, R = 0.0025 m

Number of turns, N = 200

Current through the wire, I = 0.10A

The magnitude of the magnetic field is given as:

B = (u₀NI) / (2πR)

Where u = magnetic permeability of free space.

B = (1.257 * 10⁻⁶ * 200 * 0.1) / (2 * π * 0.0025)

B = 0.0016 T

The magnitude of the Magnetic field is 0.0016 T.

3 0
4 years ago
Read 2 more answers
Clothes dryer uses about 3:00 amps of current from a 240-volt line how much power does it use
kirill115 [55]

Electrical power is defined as

P = I * V

I = 3 amperes

V = 240 volts

Power = 3 * 240

Power = 720 Watts. Answer

4 0
3 years ago
A 3-kg wheel with a radius of 35 cm is spinning in the horizontal plane about a vertical axis through its center at 800 rev/s. A
Kruka [31]

Answer:

\omega_f = 585.37 \ rev/s

Explanation:

given,

mass of wheel(M) = 3 Kg

radius(r) = 35 cm

revolution (ω_i)=  800 rev/s

mass (m)= 1.1 Kg

I_{wheel} = Mr²

when mass attached at the edge

I' = Mr² + mr²

using conservation of angular momentum

I \omega_i = I' \omega_f

(Mr^2) \times 800 = ( M r^2 + m r^2) \omega_f

M\times 800 = ( M + m )\omega_f

3\times 800 = (3+1.1)\times \omega_f

2400 = (4.1)\times \omega_f

\omega_f = 585.37 \ rev/s

3 0
4 years ago
A Scooter with a mass of 50 kilograms travels with a speed of 10 meters per second. A 2 Nt force bring it to a halt. How long ti
Serga [27]

Answer:

250s

Explanation:

Given parameters:

Mass  = 50kg

Speed  = 10m/s

Force  = 2N

Unknown:

Time the force was acting  = ?

Solution:

To solve this problem, we use the equation of motion from the second law of Newton:

            Ft  = mV

F is the force

t is the time taken

m is the mass

V is the velocity

          2  x t  = 50 x 10

               t  = 250s

3 0
3 years ago
The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the gr
Harman [31]

If the distance is proportional to the square of the time, then the distance in 9 seconds will be  (9/8)²  as long as the distance in 8 seconds.

(9/8)² = 1.265625

(64 ft) · (1.265625) = <em>81 ft. </em>

4 0
4 years ago
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