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3 years ago

True or False? Not all compounds will dissolve in water.

Chemistry

1 answer:

In-s [12.5K]3 years ago

4 0

Answer:

False

Explanation:

Polar molecules and ionic compounds dissolve in water, not nonpolar molecules

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a gas has a volume of 2.00 at 323k and 3.00 ATM What would be the new volume if the temperature is changed to 273 K in the press

Ber [7]

Answer:

$V_2 = 5.07L$

Explanation:

$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}\\V_2 = \frac{P_1 V_1 T_2}{T_1 P_2} = \frac{3.00atm \cdot 2.00L \cdot 273K}{323K \cdot 1.00atm} = 5.07L$

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1 year ago

What type of bond will form<br><br> Nitrogen and Tellurium

sineoko [7]

Answer: Vander waals

Explanation:

Tellurium is a chemical element with atomic number 52. It's symbol is Te.

Nitrogen is a chemical element with atomic number 14. Its symbol is N

VANDER WAALS bond is found between Nitrogen and Tellurium, just as in Tellurium(II) Nitrogen.

This bond is relatively weak compared to some other kinds of bonds.

That is why tellurium and most of its compounds are usually brittle and easily grounded.

So, Vander Waals bonds is the answer

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3 years ago

How does sustainable development support in a long term vision

vfiekz [6]

Explanation:

meet .google .com/sxr-wgwg-vnc

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2 years ago

Read 2 more answers

SOMEONE PLEASE HELP

Zinaida [17]

Answer:

6. 7870 kg/m³ (3 s.f.)

7. 33.4 g (3 s.f.)

8. 12600 kg/m³ (3 s.f.)

Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

1 kg= 1000g

1m³= 1 ×10⁶ cm³

Mass of iron bar

= 64.2g

= 64.2 ÷1000 kg

= 0.0642 kg

Volume of iron bar

= 8.16 cm³

= 8.16 ÷ 10⁶

$= 8.16 \times 10^{ - 6} \: kg$

$\boxed{density = \frac{mass}{volume} }$

Density of iron bar

$= \frac{0.0642}{8.16 \times 10^{ - 6} }$

= 7870 kg/m³ (3 s.f.)

$\boxed{mass = density \: \times volume}$

Mass

= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

8. Volume of brick

= 12 cm³

$= 12 \times 10^{ - 6} \: m^{3} \\ = 1.2 \times 10^{ - 5} \: m ^{3}$

Mass of brick

= 151 g

= 151 ÷ 1000 kg

= 0.151 kg

Density of brick

= mass ÷ volume

$= \frac{0.151} {1.25 \times 10^{ - 5} } \\ = 12600 \: kg/ {m}^{3}$

(3 s.f.)

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3 years ago

How many grams of sulfur are required in the preparation of 35.7 moles of sulfur dioxide Sg + O2 SO2

lidiya [134]

S+O_2-->SO_2

Its balanced already

1 mol SO_2 require 1 mole sulphur
35.7moles require 35.7mol sulphur

Mass of S

35.7(32)
1142.4g

6 0

2 years ago