Given: C3H8(g) + O2(g) ----> CO2 (g) + H2O (g)
Step : Put a 3 in front of CO2 (g) to balance C
=> C3H8(g) + O2(g) ----> 3CO2 + H2O to balance H
Step 2: Put a 4 in front of H2O
=> C3H8 (g) + O2(g) -----> 3CO2 (g) + 4H2O (g)
Step 3: Given that there are 3*2 + 4 = 10 O to the right side, put a 5 in front of O2 to balance O:
=> C3H8(g) + 5O2(g) -----> 3CO2(g) + 4H2O(g)
You can verify that the equation is balanced.
So, the answer is that the coefficient in front of O2 is 5.
Carbon dioxide can be the cause of burning carbon dioxide and a stove it depends on the heat of the flame in order for carbon dioxide to become carbon monoxide
sorry hope that helps though
Answer:
0.158 moles KMnO4
Explanation:
According to the Periodic Table,
K = 39.10 g/mol
Mn = 54.94 g/mol
O = 16.00 g/mol
KMnO4 = 39.10 g/mol + 54.94 g/mol + 4(16.00 g/mol) = 158.04 g/mol
25.0 grams KMnO4 1 mole
----------------------------- x -------------------------- = 0.158 moles KMnO4
158.04 grams
Answer:
6.72 g
Explanation:
Given data:
Mass of calcium chlorate = 13.8 g
Mass of oxygen produced = ?
Solution:
Chemical equation:
Ca(ClO₃)₂ → CaCl₂ + 3O₂
Number of moles of calcium chlorate:
Number of moles = mass / molar mass
Number of moles = 13.8 g/ 206.98 g/mol
Number of moles = 0.07 mol
Now we will compare the moles of oxygen and calcium chlorate.
Ca(ClO₃)₂ : O₂
1 : 3
0.07 : 3×0.07=0.21 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.21 mol × 32 g/mol
Mass = 6.72 g
