Answer:1.26 m/s
Explanation:
Given
translation speed of ball =3.5 m/s
Moment of inertia of ball about com 
Initial Energy

Final Energy

Equating energy as no energy loss take place



m term get cancel




Answer:
Pressure = 9.94 x 10⁶ Pascals
Explanation:
given data
mass = 51 kg
radius = 0.400 cm
solution
we know Pressure that is express as here
Pressure = total force on an area ÷ the area of the area .................1
and
Force is the woman's weight so weight will be
Weight = mass × gravity .................2
put here value
Weight = 51 × 9.8 m/s²
Weight = 499.8 Newtons
and
Area of a circle of bottom of the heel = (π) × (radius)² ...................3
put here value
Area = (π) × (0.40 cm)²
Area = 0.502654 cm²
Area = 0.0000502654 m²
and
now we put value in equation 1 we get
Pressure = force ÷ area
Pressure = 499.8 ÷ 0.0000502654
Pressure = 9943221.381 N/m²
Pressure = 9.94 x 10⁶ Pascals
Answer:
0 N
Explanation:
Magnetic force for charges moving in wire is given by
F = qvB sin θ
It can also be rewritten for a current carrying wire as
F = ILB sin θ
IL = product of the length of wire and magnitude of the current vector
B = magnetic field.
θ = the angle between the direction of current flow and the magnetic field. For this question, the direction for the two are both parallel; θ = 0°
F = IL B sin 0 = 0 N
Hope this Helps!!!
Answer:
a)
, b)
solar masses
Explanation:
Let suppose that galaxy can be treated as a puntual mass.
a) The acceleration experimented by the star is:

![a_{r} = \left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (8.0\times 10^{11})\cdot\frac{\left(1.989\times 10^{30}\,kg\right)}{\left[(6.0\times 10^{4}\,ly)\cdot \left(9.461\times 10^{15}\,\frac{m}{ly} \right)\right]^{2}}](https://tex.z-dn.net/?f=a_%7Br%7D%20%3D%20%5Cleft%286.674%5Ctimes%2010%5E%7B-11%7D%5C%2C%5Cfrac%7Bm%5E%7B3%7D%7D%7Bkg%5Ccdot%20s%5E%7B2%7D%7D%20%5Cright%29%5Ccdot%20%288.0%5Ctimes%2010%5E%7B11%7D%29%5Ccdot%5Cfrac%7B%5Cleft%281.989%5Ctimes%2010%5E%7B30%7D%5C%2Ckg%5Cright%29%7D%7B%5Cleft%5B%286.0%5Ctimes%2010%5E%7B4%7D%5C%2Cly%29%5Ccdot%20%5Cleft%289.461%5Ctimes%2010%5E%7B15%7D%5C%2C%5Cfrac%7Bm%7D%7Bly%7D%20%5Cright%29%5Cright%5D%5E%7B2%7D%7D)

The angular speed of the star is:



The period is:




b) The period is:


The angular speed is:


The acceleration experimented by the star is:


The mass of the galaxy is:

![M = \frac{\left(6.261\times 10^{-9}\,\frac{m}{s^{2}} \right)\cdot \left[(6.0\times 10^{4}\ly)\cdot (9.461\times 10^{15}\,\frac{m}{ly} )\right]^{2}}{6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} }](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B%5Cleft%286.261%5Ctimes%2010%5E%7B-9%7D%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%5Ccdot%20%5Cleft%5B%286.0%5Ctimes%2010%5E%7B4%7D%5Cly%29%5Ccdot%20%289.461%5Ctimes%2010%5E%7B15%7D%5C%2C%5Cfrac%7Bm%7D%7Bly%7D%20%29%5Cright%5D%5E%7B2%7D%7D%7B6.674%5Ctimes%2010%5E%7B-11%7D%5C%2C%5Cfrac%7Bm%5E%7B3%7D%7D%7Bkg%5Ccdot%20s%5E%7B2%7D%7D%20%7D)

Which is equal to
solar masses.