Covalent Bond Name :N6Cl10
Explanation:
- Covalent compounds are named by using numerical prefixes to identify the number of atoms in the molecule. For example Carbon Dioxide CO2 and Carbon Monoxide CO . ... Drop the double vowel for the prefix and the element of the second element in the compound.
- The three types as mentioned in the other answers are polar covalent, nonpolar covalent, and coordinate covalent. The first, polar covalent, is formed between two nonmetals that have a difference in electronegativity. They share their electron density unevenly.
- Examples of Covalent Bond: Water. An example is water. Water consists of a covalent bond containing hydrogen and oxygen bonding together to make H2O. ...Diamonds. A diamond is an example of Giant Covalent bond of carbon. A diamond has a giant molecular structure. ...Vulcanized rubber. Another example is vulcanized rubber.
- Covalent bonds are especially important since most carbon molecules interact primarily through covalent bonding. Covalent bonding allows molecules to share electrons with other molecules, creating long chains of compounds and allowing more complexity in life.
Answer:
Explanation:
The atomic radius of elements are used to estimate the sizes of elements. The atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.
To solve this problem we will obtain the atomic radius values of the given elements from a standard atomic radius table;
Si 111 pm
P 98 pm
Cl 79 pm
S 87pm
pm = picometer
We see that chlorine has the least atomic radius
An anion is an ion with a negative charge. The minus sign, when attached to the end of an ionic compound, indicates that this has a negative charge, while a plus sign indicates a positive charge.
O2- is the only compound listed that satisfied this. It is the anion.
Answer is 02-
Answer:
M of Al=33.09g or 0.0331kg
Explanation:
Heat Energy= specific heat*mass*change in temperature
H=M*C*T
make M subject of the formula
M=H/CT
M=685J/0.90J/g°C*(45°C-22°C)
M=685J/0.90J/g°C*23°C
M=685J/20.7J/g
M=33.09g or 0.0331kg
Answer is: line be long 3,011·10¹³ kilometers.
diametar of virus = 5·10⁻⁶ cm ÷ 100000 = 5·10⁻¹¹ km.
line lenght = 5·10⁻¹¹ km · 6,023·10²³.
line lenght = 3,011·10¹³ km.
Avogadro number = 6,023·10²³.
1 cm = 10⁻² m = 10⁻⁵ km.
