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strojnjashka [21]
3 years ago
8

Suppose Car 1 collides with Car 2; Car 2 was not moving. In an ideal situation with no friction, according to the Law of Conserv

ation of Momentum, what happens to the momentum within this system after the collision?
A) It remains the same.
B) It is greatly reduced.
C) It is slightly reduced.
D) It is slightly increased.
Physics
2 answers:
Jobisdone [24]3 years ago
6 0

Answer: The answer is A.

Explanation:i just took the test

insens350 [35]3 years ago
4 0
Your answer is C it is slightly reduced
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What is Speed? the ability to rest the ability to rest the ability to minimize the time cycle of a given movement the ability to
Vinvika [58]

Answer:

Speed is a scalar quantity that refers to "how fast an object is moving." Speed can be thought of as the rate at which an object covers distance. A fast-moving object has a high speed and covers a relatively large distance in a short amount of time.

Explanation:

The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time.

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A gardener uses a 60-N wheelbarrow to transport two bags of fertilizer weighing W = 252-N. Determine the maximum allowable horiz
Butoxors [25]

Explanation:

Let us assume that the maximum allowable horizontal distance be represented by "d".  

Therefore, torque equation about A will be as follows.

   60 \times 0.15 + 252 \times 0.15 \times 2 + 252 \times d = 2 \times 75 \times (0.7 + 0.15 + 0.15)

      d = \frac{[2 \times 75 \times (0.7+0.15+0.15) - 60 \times 0.15 - 252 \times 0.15 \times 2]}{252}

       d = 0.409 m

Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.

6 0
3 years ago
The following is regarding Momentum Change and Force. help is needed please!
mixer [17]

The distance travelled  is 10 m and the velocity gained at the end of this time is 2 m/s.

<h3>Velocity of the object at the end of the time</h3>

F = mv/t

where;

  • m is mass of the object
  • v is velocity of the object
  • t is time

Ft = mv

v = Ft/m

v = (50 x 10)/250

v = 2 m/s

<h3>Distance traveled by the object</h3>

v² = u² + 2as

where;

u is initial velocity = 0

a is acceleration

a = F/m

a = 50 N/ 250 kg

a = 0.2 m/s²

v² = 0 + 2as

s = v²/2a

s = (2²)/(2 x 0.2)

s = 10 m

Thus, the distance travelled  is 10 m and the velocity gained at the end of this time is 2 m/s.

Learn more about distance here: brainly.com/question/2854969

#SPJ1

4 0
2 years ago
Give two example of conditions when two objects (Object A=1 kg and Object B =10 kg) would have the same momentum.
bearhunter [10]

Answer:

they can have the momentum if only they are been divided by another number to see the difference

6 0
3 years ago
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